Ask question

Ask question

All categories

Angelina_Jolie [31]

2 years ago

8

A car travels 120m along a straight road that is inclined at 8° to the horizontal. Calculate the vertical distance through which

the car rises. (Sin8°=0.1392)

1 answer:

Genrish500 [490]2 years ago

3 0

Take a look at this pic. And, if you have any doubt, just ask!

You might be interested in

Help its for someone!!

yawa3891 [41]

Answer:

b 17/18

Step-by-step explanation:

Solve the one's in bracket then later solve everything together

5 0

3 years ago

A factory used 314. 61 kg of tomatoes to make nine batches of pasta sauce to the nearest 10th of a kilogram what quantity of tom

MatroZZZ [7]

Answer:

hello i love my cat

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please answer and put how

muminat

6 + m/4 = 3 (subtract 6 from both sides)
m/4 = -3 (multiply both sides by 4)
m = -12

Can plug in to original equation to check work:
6 - 12/4 = 3
6 - 3 = 3
3 = 3

The answer m = -12 checks out

3 0

2 years ago

Read 2 more answers

Omg I need help on this

beks73 [17]

Answer:

y = -3x - 5

Step-by-step explanation:

6 0

1 year ago

A circle is centered at the point (5, -4) and passes through the point (-3, 2).

zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

$\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10$

The standard form of equation of circle is:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where h and k are the coordinates of the center. So putting in the value:

$(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100$

8 0

2 years ago