An ordered pair (x,y) is a solution to a system of equations if it makes all the equations true.
Let's check whether (–1, 5) makes the equations true.
Plugging –1 in the first equation for x and 5 in for y, we get
–1 + 5 = 4: TRUE
Plugging –1 in the second equation for x and 5 in for y, we get
–1 – 5 = –6: TRUE
Since it makes both the equations true, it's a solution to the system of equations. So the answer choice is D, the 4th one.
Answer:
3x+4
Step-by-step explanation:
f(g(x))=3(x+2)-2
=3x+6-2
=3x+4
Answer:
he is right its A
Step-by-step explanation:
<h3>
Answer: 19</h3>
Explanation:
Let's break 110 down into its prime factors
110 = 11*10
110 = 11*2*5
110 = 2*5*11
We have three different prime factors that multiply to 110. However, the instructions say there are 4 integers that multiply to 110. To fix this, we can say
110 = 1*2*5*11
now we see that 1,2,5 and 11 multiply out to 110
They add to 1+2+5+11 = 3+16 = 19
Answer:
A. x
C. x – 5
D. x + 2
Step-by-step explanation:
From the question above, we are asked to find the factors of an algebraic expression that is given as:
x³ - 3x² - 10x
We would use the step of factorisation
Step 1
x(x² - 3x- 10)
The first factor of the algebraic expression has been obtained = x
Step 2
We factorise x² - 3x - 10
x² +2x - 5x - 10
(x²+2x) - (5x - 10)
x(x + 2) -5(x + 2)
(x + 2)(x - 5)
Step 3
x³ - 3x² - 10x
x(x² - 3x- 10)
(x)(x + 2)(x - 5)
Therefore, the factors of the algebraic expression are:
(x), (x + 2), (x - 5)
