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3 years ago

PLEASEEEE HELPPP MEEE WITHHH THISS QUESTIONN PLEASEEE!!!! I NEED A GREAT EXPLANATION PLEASEE!!!!

Mathematics

1 answer:

ipn [44]3 years ago

4 0

The diagonal of a rhombus divides it into two congruent isosceles triangles.

So ∠CBD ≅ ∠CDB

∠CBD + ∠CDB + 68 = 180

2∠CBD = 180 - 68 = 112

∠CBD = 56

We also have

∠BDE + ∠E + ∠DBE = 180

∠DBE = 180 - 73 - 36 = 71

∠EBC = ∠EBD - ∠CBD = 71 - 56 = 15

Answer: ∠EBC = 15 degrees

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In triangle ABC, mA= 40°, the length of side AB is 7 cm and the length of side BC is 5 cm. Find the measure of angle C using the

Sauron [17]

Answer:

C = 64.145º

Step-by-step explanation:

The Law of Sines is as follows:

$\frac{sinA}{a}$ = $\frac{sinB}{b}$ = $\frac{sinC}{c}$

The problem can be draw as the picture attached.

Now, the values of the sides and angles can be substituted into the Law of Sines, and because all parts are equal, only two are needed:

$\frac{sin40}{5}$ = $\frac{sinC}{7}$

Next, cross-multiply:

7sin40º = 5sinC

Then, divide both sides by 5:

$\frac{7sin40}{5}$ = sinC

Finally, take the inverse sin of the left side and convert into a decimal:

C = $sin^{-1}$ ( $\frac{7sin40}{5}$ )

C = 64.145

6 0

4 years ago

Find the measure of angle x in the figure below: A triangle is shown. At the top vertex of the triangle is a horizontal line ali

vaieri [72.5K]

Okay, I think I understand.

Straight lines have a measure of 180°, so
52° + 59° + y = 180°
y = 69°

The measure of the inner angles of a polygon = (n - 2)180° where n is the number of sides. The shape is a triangle, so n = 3.
(3 - 2)180° = 63° + y + x
180° - 63° - (69°) = x

x = 48°

6 0

3 years ago

Read 2 more answers

What property is used to find a product

s344n2d4d5 [400]

<span>The distributive property tells us how to solve equations in the form of a(b + c). The distributive property is sometimes called the distributive law of multiplication and division.
-join the gvcci gang</span>

3 0

3 years ago

Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights

krok68 [10]

Answer:

Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are $\frac{6}{8}, \frac{1}{4}, \frac{1}{6}$ that are 0.75, 0.25 and 0.17 respectively.