Cotxcos2x = 2cotx
cos2x = 2cotx/cotx
cos2x = 2
cos2x = 2cos²x - 1
2cos²x - 1 = 2
2cos²x = 2+1
2cos²x = 3
cos²x = 3/2
√cos²x = plus minus √(3/2)
cosx = plus minus √(3/2)
Get rid of the 2 in the denominator by multiplying it by 2. Then add 36 to both sides. Then your answer is 92.
The width(w) of the field is(=) 5 more(5+) than twice (2×)as long as the length(l) write equation for width
w=2l+5
Answer:
Step-by-step explanation:
Solving for the Solution Set: