4.5
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Answer:
The following Triangles are Right Triangles:
1. Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.
2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.
3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.
Step-by-step explanation:
For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.
i.e.
For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.
AC² = 365² = 133225
AB² + BC² = 76² + 357² = 1333225
∴ AC² = AB² + BC²
Hence Δ ABC a Right Triangle.
For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.
MT² = 845² = 71405
MI² + IT² = 123² + 836² = 714025
∴ MT² = MI² + IT²
Hence Δ MIT a Right Triangle.
For Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.
ML² = 101² = 10201
ME² + EL² = 20² + 99² = 10201
∴ ML² = ME² + EL²
Hence Δ MEL a Right Triangle.
Answer:
P(X is greater than 30) = 0.06
Step-by-step explanation:
Given that:
Sample proportion (p) = 0.5
Sample size = 30
The Binomial can be approximated to normal with:
To find:
P(X> 30)
So far we are approximating a discrete Binomial distribution using the continuous normal distribution. 30 lies between 29.5 and 30.5
Normal distribution:
x = 30.5, = 25,
= 3.536
Using the z test statistics;
z = 1.555
The p-value for P(X>30) = P(Z > 1.555)
The p-value for P(X>30) = 1 - P (Z< 1.555)
From the z tables;
P(X> 30) = 1 - 0.9400
Thus;
P(X is greater than 30) = 0.06