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Leno4ka [110]
3 years ago
7

What’s the difference quotient simplified

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0

\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}

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1. Is too easy it’s 300
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For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
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4x-3y=11
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Using the distributive property, we have:
4(-2)+4(y)-3y=11
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Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
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Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
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Divide both sides by 3:
3y/3 = -35/3
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This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
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The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
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Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
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agasfer [191]
7. D
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5 0
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jonny [76]
The ad will be 70.4 inches tall
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How can I use the percent equation???Ex.what number is 40% of 500???and can u solve this one,too.:45 is 25% of what number???THA
HACTEHA [7]
I've been waiting for someone to ask this question.  It's one of my favorite questions to answer.

percent means out of 100 so 1% = 1/100 and 40%=40/100 or 1/25
so for percent of a number, 'of' means multiply so 40% of 500= 40/100 times 500 or 20000/100 or 200



if you multiply a fraction by its recipricol (the number fliped upside down) the you will get 1 so if you multiply 1/2 by 2/1 then you will get 1

thus
percent is out of 100 so 1%=1/100  25%=25/100
if you represent 45 out of something as 45/x then you multiply it by the reciprocal of the fraction that is supposed to be equal (1/2 =2/4) then you will get 1
so 45/x times reciprocal of 100/25 then you will get 1/1 or 4500/25x
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so 45 is 25% of 180


The following is extra
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   but we don't know that 180 is the answer so we replace it with x then            solve for x
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3 years ago
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