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3 years ago

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The average of five numbers is 18. let the first number be increased by 1, the second number by 2, the third number by 3, the fo

urth number by 4, and the fifth number by 5. what is the average of the set of increased numbers?

1 answer:

grandymaker [24]3 years ago

6 0

It sounds like initially we have a total of 18*5 = 90. Then we are adding 5 + 4 +3 +2 +1 to this.
so that gives us 105.

105/5 = 21

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Answer:

P=0.228

Step-by-step explanation:

We know that from a faculty of six professors, six associate professors, ten assistant professors, and twelve instructors, a committee of size six is to be selected.

Therefore, we have 34 people.

We calculate the number of possible combinations:

$C^{34}_6=\frac{34!}{6!(34-6)!}=1344904\\$

Of the 6 professors we choose 2, and of the other 28 people we choose 4.

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$C_2^6\cdot C_4^{28}=\frac{6!}{2!(6-2)!}\cdot \frac{28!}{4!(28-4)!}=15\cdot 20475=307125\\$

Therefore, the probability is:

$P=\frac{307125}{1344904}=0.228$

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3 years ago

Please help, it would really make my day! I’ll give branliest if it’s correct! :-)

Morgarella [4.7K]

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Step-by-step explanation:

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3 years ago

A waiter's weekly salary can be modeled by the equation y = 0.2x + 300, where x is the amount spent by the customers in dollars

butalik [34]

Answer:

A. $100

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3 years ago

Math help questions <br>

Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of $\$800 \times 1.07^t$ .

We want the find the number of years n such that

$\$856 \times 1.07^n = \$1400$

Solve for n :

$856 \times 1.07 ^n = 1400$

$1.07^n = \dfrac74$

$\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)$

$n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)$

$n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}$

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2 years ago

Read 2 more answers

HELP PLEASE I NEED HELP

Vesna [10]

$C. \: 8 \sqrt{3}$ ✅

Step-by-step explanation:

$\sqrt{192} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3} \\ = \sqrt{ {2}^{2} \times {2}^{2} \times {2}^{2} \times 3} \\ = \sqrt{ {8}^{2} \times 3 } \\ = 8\sqrt{3}$

$\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘$

4 0

3 years ago