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kati45 [8]
3 years ago
5

The average of five numbers is 18. let the first number be increased by 1, the second number by 2, the third number by 3, the fo

urth number by 4, and the fifth number by 5. what is the average of the set of increased numbers?
Mathematics
1 answer:
grandymaker [24]3 years ago
6 0
It sounds like initially we have a total of 18*5 = 90. Then we are adding 5 + 4 +3 +2 +1 to this.
so that gives us 105.

105/5 = 21
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(3) Differentiating both sides of

2x^{3/2} + y^{3/2} = 29

with respect to <em>x</em> gives

3x^{1/2} + \dfrac32 y^{1/2} \dfrac{\mathrm dy}{\mathrm dx} = 0

Solve for d<em>y</em>/d<em>x</em> :

\dfrac32 y^{1/2} \dfrac{\mathrm dy}{\mathrm dx} = -3x^{1/2} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{-3x^{1/2}}{\frac32y^{1/2}} = \dfrac{-2x^{1/2}}{y^{1/2}} = -2\sqrt{\dfrac xy}

Then the slope of the tangent line to the curve at (1, 9) is

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The equation of the tangent line would then be

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y=\dfrac{ax+1}{x-2}

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\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{a(x-2)-(ax+1)}{(x-2)^2} = -\dfrac{2a+1}{(x-2)^2}

When <em>x</em> = -1, we have a slope of 2/3, so

-(2<em>a</em> + 1)/(-1 - 2)² = 2/3

Solve for <em>a</em> :

-(2<em>a</em> + 1)/9 = 2/3

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