The area of a triangle is given in terms of the side lengths (b, h) as
... A = (1/2)bh
If b=h, then we can find the side length as ...
... A = (1/2)b²
... b = √(2A) . . . . . multiply by 2 and take the square root
The hypotenuse (x) can be found from the Pythagorean theorem:
... x² = b² + h² = 2b²
... x = b√2
The perimeter is the sum of the side lengths, so is
... P = b + b + x = 2√(2A) + (√(2A))·√2
... P = (2+√2)·√(2A)
Answer:
Solution given:
f(x) =
x-2
let f(x)=y
y =
x-2
interchanging role of x and y
x=
y-2
x+2=
y
y=9(x+2)
y=9x+18
So
<u>F</u><u>-</u><u>¹</u><u>(</u><u>x</u><u>)</u><u>=</u><u>9</u><u>x</u><u>+</u><u>1</u><u>8</u>
<u>a</u><u>n</u><u>d</u>
<u>F</u><u>-</u><u>¹</u><u>(</u><u>-</u><u>1</u><u>)</u><u>=</u><u>9</u><u>*</u><u>-</u><u>1</u><u>+</u><u>1</u><u>8</u><u>=</u><u>-</u><u>9</u><u>+</u><u>1</u><u>8</u><u>=</u><u>9</u>
Answer:
Step-by-step explanation:

d) Let the cost of one group lesson be x and one private lesson be y

This sequence seems to apply -9, +13, +6 repeatedly.
So after the 34, the -9 has to be applied. The next number would be 25.