(5/6) / (1/4)
5/6 * 4/1
20/6
3 1/3 <=== there is 3 1/3 one-forth lb servings
Answer:
(-2, 4) (3, 6)
Step-by-step explanation:
I think this would be correct? haha
y2-y1/x2-x1
6-4=2,3--2(or 3+2 because 2 negatives make a positive)=5, so 2/5.
I hope this helps :)
Answer:
You want to solve for x, the first thing you need to do is distribute
The 2 through the x+4 then the other 2 through the -8-x
2(x+4)= 2x+8
2(-8-x)= -16-2x
2x+8=-16-2x-2x (combine like terms on the right side)
2x+8=-16-4x (now subtract 8 from each side)
2x=-24-4x (8-8=0, -16-8=-24) (now add 4x to each side)
6x=-24 (-4x+4x=0, 2x+4x=6x), (divide each side by 6)
x=-4 (6/6=1, -24/6=-4)
x=-4
Hope this helps ;)
Answer:
• multiplied by 4p: (x -h)² +4pk = 0
• zeros for k > 0: none
• zeros for k = 0: one
• zeros for k < 0: two
Step-by-step explanation:
a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...
(x -h)² +4pk = 0
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b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)
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c) As in part b, the value of k defines the vertex location. When it is zero, the vertex of the parabola is on the x-axis, so there is one real zero (It is considered to have multiplicity 2.)
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d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.
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The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.
Answer:
11(4h-3)
Step-by-step explanation:
The greatest known common factor of 44h and 33 is 11. So using the distributive property, I got 11(4h-3)