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3 years ago

Two years ago a father was four times as old as his son. Three years from now the father will be only three times as old

Mathematics

1 answer:

vampirchik [111]3 years ago

6 0

Answer:

c. 3x + 15

The son is currently 12 years old.

The father is currently 42 years old.

Step-by-step explanation:

x = the son's age 2 years ago

x + 2 = the son's age in the present

x + 5 = the son's age 3 years from now

f = the father's age 2 years ago = 4x

f + 2 = the father's age in the present = 4x + 2

f + 5 = the father's age 3 years from now = 3(x + 5) = 4x + 5

*3(x + 5) when distributed is equivalent to 3x + 15

4x + 5 = 3x + 15

x + 5 = 15

x = 10

This means that:

Present age of the son: (10) + 2 = 12 years old

Present age of the father: 4(10) + 2 = 42 years old

~Hope this Helps!~

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