Answer:
I got that AE^2 = 8EC^2
Step-by-step explanation:
Here's what I did. I probably did this wrong, but this might give you an idea on how to solve it.
First, create equations:
AB = BC = AC = DE = 2EC
BD= BC = EC
Then, I used pythagorean theorem (since AD is perpendicular to BC): AD^2 + DE^2 = AE^2
Substitute: (2EC)^2 + (2EC)^2 = AE^2
Simplify: 4EC^2 + 4EC^2 = AE^2
AE^2 = 8CE^2
Answer:
14
Step-by-step explanation:
It seems to be a dilation of 1/2
Your welcome
Hope this helps
Pls mark brainliest, I really need it
- massmaster34
Answer:
3:15PM
Step-by-step explanation:
If If Diana got out of school at 1:40 P.M, this and spent 1 hour 35 minutes at the rehearsal, to know the time that the choir rehearsal ends, we will have to add the time spent at rehearsal to the time he got out of school;
1:40 P.M + (1hr 35 minutes)
1:40 P.M + 1 hr = 2:40PM
2:40PM + 35mintes = <u>2:40PM + (20mintes) +15 minutes</u>
[2:40PM + (20mintes)] +15 minutes = 3:00pm + 15 minutes
3:00pm + 15 minutes = 3:15PM
Hence the choir rehearsal ends at 3:15PM