All categories

3 years ago

Josh made 8 3/4 cups of jello. if he serves it in 1/2 cup servings, how many people can he serve?

Mathematics

1 answer:

juin [17]3 years ago

3 0

Answer: 17 people

Step-by-step explanation:

You divide 8 3/4 and 1/2 and you get 17 1/2

And since the question asks how many people can he serve you use the whole number because its not fair if you give a full serving to a person and half a serving to another.

You might be interested in

A tree cast a shadow of 30m long and a 2m stick casts one that is 3m long. As show in the below diagram how tall is the tree?

PSYCHO15rus [73]

Answer:

20 m

Step-by-step explanation:

<u>We have similar triangles here.</u>

BC║DE, AB║AD and AC║AE ⇒ ΔADE ~ ΔABC

<u>The ratio of corresponding sides of similar triangles is same:</u>

BC/DE = AC/AE
BC / 2 = 30/3
BC / 2 = 10
BC = 2*10
BC = 20 m

6 0

3 years ago

Read 2 more answers

What fraction of a gallon is a quart

cluponka [151]

Answer:

1/4 gallon

Step-by-step explanation:

4 quarts = 1 gallon, so 1 quart = 1/4 gallon.

3 0

3 years ago

Una heladeria dispone de 20 frutas distintas para elaborar sus malteadas. Si los clientes pueden elegir tres sabores para mezcla

Dahasolnce [82]

Answer:

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

Step-by-step explanation:

En este caso, el cliente que adquiere una malteada de tres sabores distintos sigue el siguiente procedimiento:

1) El primer sabor sale de cualquiera de las 20 frutas disponibles.

2) El segundo sabor es distinto al primer sabor, es decir, que sale de las 19 frutas restantes.

3) El tercer sabor es distinto al primer sabor y al segundo sabor, es decir, que sale de las 18 frutas restantes.

Puesto que existe una doble conjunción y que puede importar el orden según la preferencia del cliente, se habla matemáticamente de una permutación, definida como:

$n\mathbb{P}k = \frac{n!}{(n-k)!}$ (1)

Donde:

$n$ - Número de sabores disponibles, adimensional.

$k$ - Número de sabores escogidos, adimensional.

Si tenemos que $n = 20$ y $k = 3$ , entonces la cantidad de malteadas de tres sabores distintos es:

$n\mathbb{P}k = \frac{20!}{(20-3)!}$

$n\mathbb{P}k = \frac{20!}{17!}$

$n\mathbb{P}k = 20\cdot 19\cdot 18$

$n\mathbb{P}k = 6840$

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

5 0

3 years ago

PLEASE HELP ME I WILL MARK YOU BRAINLIEST FOR THIS ANY ANSWERS!!!)Mr. Perez designs a probability model to help him predict whic

Nesterboy [21]

Answer:

Number A. is True. B. is False. C. is IDK D. is False. E. is true.

Step-by-step explanation:

If you read it you can tell plus I broke it down and solved it on paper.

6 0

3 years ago

Read 2 more answers

Can you solve 5a please greatly appreciated.

timurjin [86]

Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5

Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)

3 0

3 years ago