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Stella [2.4K]
3 years ago
5

Of the following sets, which numbers in {1, 2, 3, 4, 5} make the inequality 3x + 1 > 4 true?

Mathematics
1 answer:
Kazeer [188]3 years ago
5 0
The answer is 2,3,4,5  hope that helps
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What is the volume of a sphere with a radius of 5.9 inch rounded to the nearest 10th of a cubic inch
ololo11 [35]

Answer:

860.3

Step-by-step explanation:

43·π·5.93≈860.28954in³

860.28954 = 860.3

4 0
2 years ago
Help me!!! I need help ASAP
tia_tia [17]

9514 1404 393

Answer:

  y = 3.02x^3 -5.36x^2 +5.68x +8.66

Step-by-step explanation:

Your graphing calculator (or other regression tool) can solve this about as quickly as you can enter the numbers. If you have a number of regression formulas to work out, it is a good idea to become familiar with at least one tool for doing so.

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If you're trying to do this by hand, the x- and y-values give you 4 equations in the 4 unknown coefficients.

  a·1^3 +b·1^2 +c·1 +d = 12

  a·3^3 +b·3^2 +c·3 +d = 59

  a·6^3 +b·6^2 +c·6 +d = 502

  a·8^3 +b·8^2 +c·8 +d = 1257

Solving this by elimination, substitution, or matrix methods is tedious, but not impossible. Calculators and web sites can help. The solutions are a = 317/105, b = -75/14, c = 1193/210, d = 303/35. Approximations to these values are shown above.

8 0
2 years ago
Eight thousand six and thirty-four thousandths<br> * Write as a decimal
valentinak56 [21]

Answer:

8,006.034

Step-by-step explanation:

eight thousand six = 8,006

and = .

thirty-four thousandths = .034

5 0
3 years ago
Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (
Vladimir79 [104]

Answer:

Factors: (x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

Step-by-step explanation:

We are given a polynomial:

f(x)=x^4-x^3-2x-4

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

8 0
2 years ago
IM BEGGING SOMEONE PLEASE HELP!!!!
PtichkaEL [24]

Answer:

Option C. y ≤ x-2

                y ≤ 50/9-(1/6)x-(1/18)x^2

Step-by-step explanation:

Please, see the attached files.

Thanks.  

6 0
3 years ago
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