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Natasha2012 [34]
3 years ago
9

What is the radius of C? 5 cm 10 cm 12.5 cm 50 cm

Mathematics
1 answer:
fomenos3 years ago
8 0

Answer:

Just copy and paste the question and there will be at least 2 to 3 sites with  the answer

Step-by-step explanation:

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In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AC=5 and BH=2, find AH and CH.
Yakvenalex [24]

Answer:

  AH = 1 or 4

  CH = 4 or 1

Step-by-step explanation:

An altitude divides a right triangle into similar triangles. That means the sides are in proportion, so ...

  AH/BH = BH/CH

  AH·CH = BH²

The problem statement tells us AH + CH = AC = 5, so we can write

  AH·(5 -AH) = BH²

  AH·(5 -AH) = 2² = 4

This gives us the quadratic ...

  AH² -5AH +4 = 0 . . . . in standard form

  (AH -4)(AH -1) = 0 . . . . factored

This equation has solutions AH = 1 or 4, the values of AH that make the factors be zero. Then CH = 5-AH = 4 or 1.

3 0
3 years ago
Apy is a(n) _____
Harrizon [31]

Answer:

Interest rate avertised by borrowers

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E
Gnoma [55]

Answer:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

Step-by-step explanation:

Given

\triangle ABC {\displaystyle \sim } \triangle DE\ F

AC = 10

AB = 5

\angle C = 30^\circ

ED = 7.5

DF = 25

\angle F =30

\angle E =90

Required

Which of the options is/are true:

\triangle CBA {\displaystyle \sim } \triangle FED            \triangle CBA {\displaystyle \sim } \triangle FDE              \triangle BAC {\displaystyle \sim } \triangle EFD

\triangle BAC {\displaystyle \sim } \triangle EDF            \triangle ABC {\displaystyle \sim } \triangle DE\ F             \triangle ABC {\displaystyle \sim } \triangle DFE

The given triangles, implies that:

A {\displaystyle \sim } \ D

B {\displaystyle \sim } \ E

C {\displaystyle \sim } \ F

By taking each sides of both triangle, one after the other; the possible similar triangles are:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

5 0
3 years ago
 what is 0.3 x0.6 this is new to me
Ivan
0.3 * 0.6

6*3 = 18

0.18
3 0
3 years ago
Read 2 more answers
42 divided by 6 in repeated subtraction
Wittaler [7]
42 - 6 = 36 - 1 36 - 6 = 30 - 2 30 - 6 = 24 - 3 24 - 6 = 18 - 4 18 - 6 = 12 - 5 12 - 6 = 6 - 6 6 - 6 = 0 - 7 42/6 = 7
4 0
3 years ago
Read 2 more answers
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