Ask question

Ask question

All categories

3 years ago

5

A park is shaped like a trapezoid. It has an area of 7.2 square miles. One base is 1.2 miles, and the other base is 2.4 miles lo

ng. What is the height of the park?

1 answer:

WINSTONCH [101]3 years ago

6 0

7.2÷(1.2+2.4)=2
2÷.5=4
So the height equals 4

You might be interested in

I need help please no need for step by step.

Klio2033 [76]

Sorry you dont have a picture so i can not help

4 0

2 years ago

Read 2 more answers

I need help for this. it would be amazing if you drew out the problem <3

kondor19780726 [428]

Answer:

21245489

Step-by-step explanation:

231

1

1

6

6

6456464163

7 0

3 years ago

Read 2 more answers

Help for these 3 right answer will get brainliest.

Irina18 [472]

Answer:

will you help me with grade 9 math, algebra 2 please

Step-by-step explanation:

4 0

3 years ago

Another set of help? i need a hand lol

Zepler [3.9K]

Answer: C=14π≈43.98 ft

Step-by-step explanation:

To find the circumference of the circle, we use the equation C=2πr or C=πd. These 2 equations are equivalent because 2r is the same as d, diameter. In this case, we can use C=πd because the problems already gives us the diameter.

C=πd

C=14π≈43.98 ft

I hope this helps!

5 0

3 years ago

Which of these limits evaluate to 0?

Vikentia [17]

<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

$\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\$

----------

Part II

$\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\$

----------

Part III

$\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\$

7 0

3 years ago