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atroni [7]
2 years ago
8

Find the sum of 5x^2y and (2xy^2+x^2y)

Mathematics
2 answers:
zlopas [31]2 years ago
8 0

6x^2y+2xy^2 and it’s bionomial

Ilya [14]2 years ago
5 0
5(x^2)(y)+(2(x)(y^2)+(x^2)(y))
5(x^2)(y)+2(x)(y^2)+(x^2)(y)
6(x^2)(y)+2(x)(y^2)
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What is the range of y=5(11)x
dem82 [27]

Answer:

Domain: ( − ∞ , ∞ ) ,  { x | x ∈ R}

Range: ( − ∞ , ∞ ) ,  { y | y ∈ R}

Step-by-step explanation:

We can simplify to understand how to answer the question better.

<em>5 * 11x = 55x</em>

<u>Function range definition:</u><u> </u>

The set of values of the dependent variable for which a function is defined.

  • The range of polynomials with odd degree is all real numbers.

<u>So the solution is.. </u>

-∞<x< ∞

<u>And the interval notation is..</u>

(- ∞. ∞)

7 0
2 years ago
Find a point-slope form for the line with slope 1/5<br> and passing through the point (-7,-4).
Basile [38]

Answer:

y + 4 = ⅕(x + 7)  

Step-by-step explanation:

The "point-slope" form of the equation of a straight line is:

y − y₁ = m(x − x₁)

where m is the slope and (x₁, y₁) is a point on the line.

If m = ⅕ and (x₁, y₁) = (-7,  - 4), the point-slope equation is

y + 4 = ⅕(x + 7)

The Figure below shows the graph of your line and a point at (-7, -4).

6 0
3 years ago
What is the value of x in the equation -5/8x = -160?
Brut [27]

Answer:

Step-by-step explanation:

-5           -160

----      =  ------

8x            1

Cross multiply

-1280x = -5

Divide both sides of the equation by -152

x = 256

I hope it helps :)

3 0
3 years ago
Read 2 more answers
NEED HELP FAST PLEASE!!!
Vinil7 [7]

Answer:

I can't see it that good can you text it in please

Step-by-step explanation:

6 0
2 years ago
(01.01 MC)Why is 2 + (−3) equal to −1
tino4ka555 [31]

2+(-3) = -1

2- 3 = -1

-1=-1

The question is why though ?

It is because you keep the negative exponent which is with the biggest number. So this is how its look like +2 -3, so 3 is bigger then 2 so for that reason you keep the negative sign.


I hope that's help:)

3 0
2 years ago
Read 2 more answers
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