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levacccp [35]
2 years ago
6

What is the slope of a line that passes through the points (8,5) and (13,2)?

Mathematics
2 answers:
almond37 [142]2 years ago
6 0

Answer:

I believe it is -0.6

Step-by-step explanation:

subtract 8,5 by 13,2 and you should get (-0.6)

miss Akunina [59]2 years ago
6 0

Answer:

the slope would be -3/5 or -0.6

Step-by-step explanation:

because the line that would pass through those points would be -3/5x+9.5=y

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If in a sample of 355 adult males, we have a mean total cholesterol level of 185 mg, with s = 16. What is the 95% confidence int
sladkih [1.3K]

Answer:

Step-by-step explanation:

We want to determine a 95% confidence interval for the mean total cholesterol level of all males.

Number of sample, n = 355

Mean, u = 185 mg

Standard deviation, s = 16

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

185 +/- 1.96 × 16/√355

= 185 +/- 1.96 × 0.849

= 185 +/- 1.66404

The lower end of the confidence interval is 185 - 1.66404 =183.336

The upper end of the confidence interval is 185 + 1.66404 = 186.66

Therefore, with 95% confidence interval, the mean total cholesterol level of all males is between 183.336 mg and 186.66 mg

5 0
3 years ago
What is y-1 =2(x +3) in standard form?
miv72 [106K]

Answer:

y-1=2(x+3)

y-1=2x+6

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y=2x+7

6 0
3 years ago
plz help. The amount of pages in a 3rd graders book can be modeled by f(x) = x^2 + 6x where x represents the number of chapters.
posledela

Answer:

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6 0
3 years ago
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

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3 years ago
Due in 15 please help!!!
Deffense [45]

Answer:

Step-by-step explanation:

its true

4 0
2 years ago
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