Answer:
B
Step-by-step explanation:
I had the same question
Adding a negative is same as subtraction
-5+78-32
73-32
41
Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
Answer:
the answer would be 6 x 4 x 9 x 5 x 2
Answer:
197.92
Step-by-step explanation:
pretty simple not hard bub