Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
m = 28
Step-by-step explanation:
70 × 2 = 5m
140 = 5m
28 = m
248/4=62
62•7 1/2=465 miles
He will go 465 miles in 7 hours and 30 minutes
Answer:
60 girls play sports
Step-by-step explanation:
#1- divide 105 by 7=15
#2- multiply 4 by 5= 60
therefore 60 of the 105 girls play sports
Answer:
95/6
3/5
Step-by-step explanation: