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3 years ago

Can you help me please?! :)

Mathematics

1 answer:

UkoKoshka [18]3 years ago

3 0

The answer is A
start by isolating the y variable
the rest of the work is shown here

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What is the value of 32 to the 4th power

True [87]

32 can be rewritten as;
$2^{4} *2$

5 0

3 years ago

-2x + 3y = 18. x = -y + 1

Bezzdna [24]

Answer:

D. X=-3, y=4

Step-by-step explanation:

-2x+3y=18 equation 1

x=-y+1 equation 2

-2(-y+1)+3y=18 replace x value of equation 2 into equation 1

2y-2+3y=18

5y=20

y=4

solve for x by replacing y value into either equation.

x=-y+1

x=-4+1

x=-3

8 0

3 years ago

What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y

Mumz [18]

Answer:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Step-by-step explanation:

The question is poorly formatted.

Given

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Required

Derive an equivalent expression

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Express 18 as 9 * 2

$\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}$

Split the expression as follows:

$\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}$

Take positive square root of 9

$\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}$

$\sqrt[3]{2y^3} * 21 * \sqrt{2y}$

$21*\sqrt[3]{2y^3} * \sqrt{2y}$

The cube root can be rewritten to give:

$21*\sqrt[3]{2}*\sqrt[3]{y^3} * \sqrt{2y}$

$\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y$

So, we have:

$21*\sqrt[3]{2} * y * \sqrt{2y}$

Rewrite as:

$21y *\sqrt[3]{2} * \sqrt{2y}$

Split $\sqrt{2y$

$21y *\sqrt[3]{2} * \sqrt{2} * \sqrt{y}$

Collect Like Terms

$21y*\sqrt{y} *\sqrt[3]{2} * \sqrt{2}$

Represent in index form

$21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}$

Apply law of indices

$21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }$

$21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}$

$21*y^{\frac{3}{2}} *2^{\frac{5}{6}}$

$21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Hence:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

6 0

3 years ago

1/4 times a number is -12.<br><br><br> one step equations

alexgriva [62]

Answer:

1/4x = -12

X=-48

8 0

3 years ago

A deep freezer has a temperature of -6°C when it is turned off.

Xelga [282]

Answer:

y = -6 + 1.2*x is the answer I would use, but see the note below.

Step-by-step explanation:

Let x = the number of minutes.

Let y = the temperature at any given time.

y = -6 + 1.2*x

This is the equation that you would use if you were calculating y with a calculator. If you are in a chemistry class it should be written as

y = - 6°C + 1.2°x/ min

4 0

3 years ago