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2 years ago

Can someone help me with this?

Mathematics

1 answer:

salantis [7]2 years ago

3 0

Answer:

[See Below]

Step-by-step explanation:

✦ The pattern is y ÷ 8. (So just divided by 8 each time.)

✧ 512 ÷ 8 = 64

✧ 64 ÷ 8 = 8

✧ 8 ÷ 8 = 1

✧ 1 ÷ 8 = 0.125

✧ 0.125 ÷ 8 = 0.015625

✦ So then the next values would be:

✧ 8⁰ = 1

✧ 8⁻¹ = 0.125

✧ 8⁻² = 0.015625

~Hope this helps Mate. If you need anything feel free to message me.

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Mkey [24]

9514 1404 393

Answer:

4mn/(3m+12)

Step-by-step explanation:

It is often helpful to factor expressions so that common factors can cancel.

$\dfrac{8n^2}{m^2-16}\times\dfrac{m^2-4m}{6n}=\dfrac{8mn^2(m-4)}{6n(m-4)(m+4)}=\dfrac{4mn}{3(m+4)}\\\\=\boxed{\dfrac{4mn}{3m+12}}$

3 0

2 years ago

Pawl,colin and bria are waiters. One night the restaurant earns tips totalling £78.40 the share the tips in the ratio 2.1.5 how

stellarik [79]

Answer: Brian gets $39.2 more over Colin.

Step-by-step explanation:

Given: Total tip amount = £78.40

The ratio of the share of tips for Pawl, Colin and Bria is 2:1 :5.

Let tip amount for Pawl = 2x, tip amount for Colin = x , tip amount for Bria = 5x

Then, 2x+x+5x= 78.40

$\Rightarrow\ 8x = 78.40\\\\\Rightarrow x=\dfrac{78.40}{8 }\\\\\Rightarrow x=9.8$

Tip for Colin = $ 9.8 , Tip for Bria = 5($9.8)= $49

Difference = $(49-9.8) = $ 39.2

Hence, Brian gets $39.2 more over Colin.

4 0

3 years ago

Simplfy <br> 2x+4/-3 = 12

nasty-shy [4]

So you have the equation (2x+4)/-3=12
Multiply by -3 on each side.
2x+4=-36
2x=-20
x=-10
Hope this helps.

4 0

3 years ago

Select all expressions that are equivalent to 64

pochemuha

Answer:

Step-by-step explanation:

What do you man what expressions or just expressions in general.

4 0

3 years ago

Drag each function to the correct location on the chart. Classify the functions as continuous and discontinuous functions. If a

Ilia_Sergeevich [38]

Answer:

Continuous: g(x) and j(x)

Removable: h(x) and m(x)

Infinite: f(x) and i(x) and k(x)

Jump: l(x)

Step-by-step explanation:

5 0

2 years ago

Can someone help me with this?​

Can someone help me with this?