¿cuántas raíces cuadradas tiene el número 0?

Mathematics

1 answer:

DanielleElmas [232]2 years ago

7 0

Answer:

one

Step-by-step explanation:

Zero has one square root which is 0.

Negative numbers don't have real square roots since a square is either positive or 0.

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We know that February has either 28 or 29 days, but there is a year in the future, February will have 30 days

Karo-lina-s [1.5K]

Answer:

The year 2020 is a leap year, which means February will have 29 days rather than 28, and the overall number of days will be 366 rather than 365. This was also the case in 2016, and the year 2024 will be a leap year once more.

Step-by-step explanation:

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3 years ago

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$