Answer:
The answer is 1/8
Step-by-step explanation:
Hope this helps. So the question is asking you odds of 8 which is the denominator already. So then it asks the odd to pick eight. So thats how i got 1/8.
Answer:
Part A: The population are the American adult citizens, excluding the ones from Alaska and Hawaii. The population is the people which the sample is trying to represent, as a hole.
The sample is a portion of this population, and in this case is represented by a randomly selected amount of people whose response to the interview has been selected.
Part B: The sample here has been selected in two steps. The first step is the one that we must pay attention to: the numbered list of one million responses from around the US (excluding Alaska and Hawaii). Because these responses were obtained by an online survey, the sample looks like a convenience sampling, as it depends on the availability and willingness from participants to take part of the study (is not compulsory for everyone, so not everyone is going to response, then there are people that is not going to be represented by). The second step is the random selection of a part of the previous responses. This last part will ensure that, the individuals that took part of the group that was interviewed, are well represented in the results.
Part C: As it was mentioned, there is a selection bias, because the information from the sample comes from a specific group of people that has certain features that may not represent all American adults citizens. For example, the opinion of those people who do not use internet, will not be considered (and they may be a large number of persons). This situations weaken the conclusions obtained in the study, as they are not representative of the hole population.
Step-by-step explanation:
Answer:
We know that volume of cuboid $$=\l ength \times breadth \times height$$
V=3×2×5
V=30 m
3
Now, we know that 1 m
3
=1000 L
So,
V=30×1000 L
V=30000 L
Mark brainliest please
Hope this helps you
Answer:
Step-by-step explanation:
Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).
To find: coordinates of vertex of the right angle
Solution:
Let C be point 
Distance between points 
is given by 
ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)
![34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]](https://tex.z-dn.net/?f=34%3D%5Cleft%20%5B%20%28x-4%29%5E2%2B%28y-1%29%5E2%20%5Cright%20%5D%2B%5Cleft%20%5B%20%28x%2B1%29%5E2%2B%28y%2B2%29%5E2%20%5Cright%20%5D)
Put 
![34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34](https://tex.z-dn.net/?f=34%3D%5Cleft%20%5B%20%28-1-4%29%5E2%2B%281-1%29%5E2%20%5Cright%20%5D%2B%5Cleft%20%5B%20%28-1%2B1%29%5E2%2B%281%2B2%29%5E2%20%5Cright%20%5D%5C%5C34%3D25%2B9%5C%5C34%3D34)
which is true. So, 
can be a vertex
Put 
![34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34](https://tex.z-dn.net/?f=34%3D%5Cleft%20%5B%20%284-4%29%5E2%2B%28-2-1%29%5E2%20%5Cright%20%5D%2B%5Cleft%20%5B%20%284%2B1%29%5E2%2B%28-2%2B2%29%5E2%20%5Cright%20%5D%5C%5C34%3D9%2B25%5C%5C34%3D34)
which is true. So, 
can be a vertex
Put 
![34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22](https://tex.z-dn.net/?f=34%3D%5Cleft%20%5B%20%281-4%29%5E2%2B%281-1%29%5E2%20%5Cright%20%5D%2B%5Cleft%20%5B%20%281%2B1%29%5E2%2B%281%2B2%29%5E2%20%5Cright%20%5D%5C%5C34%3D9%2B4%2B9%5C%5C34%3D22)
which is not true. So, 
cannot be a vertex
Put 
![34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22](https://tex.z-dn.net/?f=34%3D%5Cleft%20%5B%20%282-4%29%5E2%2B%28-2-1%29%5E2%20%5Cright%20%5D%2B%5Cleft%20%5B%20%282%2B1%29%5E2%2B%28-2%2B2%29%5E2%20%5Cright%20%5D%5C%5C34%3D4%2B9%2B9%5C%5C34%3D22)
which is not true. So, 
cannot be a vertex
Put 
![34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30](https://tex.z-dn.net/?f=34%3D%5Cleft%20%5B%20%284-4%29%5E2%2B%28-1-1%29%5E2%20%5Cright%20%5D%2B%5Cleft%20%5B%20%284%2B1%29%5E2%2B%28-1%2B2%29%5E2%20%5Cright%20%5D%5C%5C34%3D4%2B25%2B1%5C%5C34%3D30)
which is not true. So, 
cannot be a vertex
Put 
![34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70](https://tex.z-dn.net/?f=34%3D%5Cleft%20%5B%20%28-1-4%29%5E2%2B%284-1%29%5E2%20%5Cright%20%5D%2B%5Cleft%20%5B%20%28-1%2B1%29%5E2%2B%284%2B2%29%5E2%20%5Cright%20%5D%5C%5C34%3D25%2B9%2B36%5C%5C34%3D70)
which is not true. So, 
cannot be a vertex
So, possible points for the vertex are
Answer:
http://mansfieldalgebra1.weebly.com/uploads/1/0/4/4/10447339/rc_2_answer_key.pdf
Step-by-step explanation:
