A^2+b^2= C^2 solve for A
1 answer:
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In the Figure below is shown the graph of this function. We have the following function:
The occurs when
, so:
Therefore, the is the given by the point:
From the figure we have three :
So, the occur when
. Thus, proving this:
Answer:
This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).
Step-by-step explanation:
The given function is
To find , we substitute
into the function.
To find , we substitute
into the function.
To find , we must first find
.
This implies that;
For this function to satisfy the Rolle's Theorem;
It must be continuous on .
It must be differentiable on .
and
.
All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.