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3 years ago

89,999 rounded to the nearest hundred thousand

Mathematics

2 answers:

lys-0071 [83]3 years ago

7 0

The answer is 90,000

tia_tia [17]3 years ago

3 0

90,000, because you would look at the ten thousands. The number there is a 9 so you would round up to 90,000.

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Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

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So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

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3 years ago

A car dealership uses the linear model y = -1100x + 25000 to

Amiraneli [1.4K]

Answer:

Graph the line using the slope and y-intercept, or two points.

Slope:

−

1000

-1000

y-intercept:

(

25000

)

(0,25000)

25000

xy025000250

Step-by-step explanation:

(づ￣ ³￣)づ

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2 years ago