Answer:
100% or 1
Explanation:
This question involves a gene coding for fur color in bears. According to the question, black fur allele (B) is dominant over the brown fur allele (b). This means that a bear heterozygous for fur color (Bb) will be phenotypically black.
In this question, a black father bear (genotype BB) and a brown mother bear (genotype bb) were crossed, the baby bears will all have a genotype Bb (see punnet square in the attached image). Since all the offsprings of this cross have genotype Bb, this means that 100% will have black fur.
A Tree or a living thing. AS apposed to abiotic, meaning nonliving.
ex. a rock.
Answer:
1. How did the tidal wave affect the predicted frequencies of the alleles in the population?
No changes
2. What is the frequency of the recessive allele?
q= 0.6
Explanation:
If we assume that all individuals were equally likely to be wiped out, that means the frequency/ratio of the gene and genotype of the population will not change. The tidal wave killing 100 out of 200, so it simply makes the population become half of it used to be.
If the population at equilibrium, we can use the Hardy-Weinberg formula to find out the expected frequency of the dominant and recessive alleles. There are 36 homozygous recessives out of 100, so the frequency of the recessive allele will be:
q^2 = 36/100
q= √36/100= 6/10= 0.6
<h2>Answer:</h2>
Bacteria provide genetic engineers with <u>_vector_ </u>and <u>_host_.</u>
<h3>Explanation:</h3>
Vector are vehicles or carriers which are used to carry the gene of interest. They are usually plasmids which are bacterial circular genome which can replicate independently.
Hence bacterial plasmids are used for the insertion of gene of interest and its transfer to the host cell.
As plasmids is taken from the bacteria, so mostly bacteria is used as the host for the gene of interest.
