Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
What is the question to your problem? Sorry...
Answer:
b =0
Step-by-step explanation:
The only value where |b| = -b is when b=0
|0| = -0
0 = 0
Absolute value means non- negative
non-negative = negative
This is only true when we equal zero
The answef is 1.83 because if you notice all of them are being divided by 38your answer is 16.5 because youre dividing all dog food in cups by wet food 3 times like 4.5/3 is 1.5 and so on