1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arisa [49]
3 years ago
12

Nicole is working two summer jobs, making $10 per hour babysitting and making $20 per hour tutoring. In a given week, she can wo

rk at most 17 total hours and must earn a minimum of $250. If Nicole worked 2 hours babysitting, determine all possible values for the number of whole hours tutoring that she must work to meet her requirements. Your answer should be a comma separated list of values.

Mathematics
1 answer:
ryzh [129]3 years ago
8 0

Answer:

she needs to work at least 12 hours tutoring,

Step-by-step explanation:

You might be interested in
Suppose that we have constructed a 95% confidence interval for the true mean salary of graduating business majors: (50k, 70k). B
slava [35]

Answer:

d. 60k

Step-by-step explanation:

The sample mean is the midpoint between the lower and the upper limit of the confidence interval, that is, the sum of the lower and the upper limit divided by 2.

In this problem, we have that:

Lower limit: 50k

Upper limit: 70k

(50k + 70k)/2 = 60k

So the correct answer is:

d. 60k

4 0
3 years ago
A person made $16210 how much made an hour
Flauer [41]

[tex]16210/60 (seconds) = 270.16

around $270

hope this helps

4 0
3 years ago
Read 2 more answers
The polynomial x^2-(k+1)x-3 has a factor (x-k+1). find k
astra-53 [7]

Answer:

p

Step-by-step explanation:

please help some one I also need help on this

6 0
3 years ago
Someone please help me ive been trying this problem for 30 minutes
Rina8888 [55]
For q(x) = -2x - 2 and r(x) = x^2 + 2

Find the value of q(r(3)).

This is a problem that asks for you to find a function of a function. First things first, you must understand that it is asking you to plug r(3) into q(x) as the value of x. 

Let's start by plugging 3 into r(x). Doing so, you'd get
r(3) = 3^2 + 2

Solve it. 
r(3) = 9 + 2
r(3) = 11

You can see now that q(r(3)) is really q(11). Plug it in.
q(r(3)) = -2(11) - 2

Solve it. 
q(r(3)) = -22 - 2
q(r(3)) = -24


3 0
3 years ago
Read 2 more answers
The sum of 3 consecutive odd integers is 36. Whal<br> consecutive odd integers
IgorC [24]

\huge\pink{Answer}

Any odd number can be represented with 2n+1 where n is a whole number. Also, since the next consecutive number will be even (2n+1+1), then the next consecutive odd number must be 2n+1+2, or 2n+3. Since consecutive odd numbers are separated by 2, then the previous odd number should be 2n-1. So:

<h3>2n-1+2n+1+2n+3=36</h3><h3>6n+3=36</h3><h3>6n+3-3=36-3</h3><h3>6n/3=33/3</h3><h3>2n=11</h3>

Now in order to find three odd consecutive numbers that will sum to 36, you must be able to divide 11 evenly by 2, and have a whole number as a result. This is impossible, so there aren't any 3 odd numbers that will sum to 36.

<h2>HOPE IT HELPS ☺️</h2>

5 0
3 years ago
Other questions:
  • The length of the hypotenuse is:<br><br> 6.<br> 12.<br> 36.<br> <img src="https://tex.z-dn.net/?f=6%20%5Csqrt%7B3" id="TexFormul
    10·1 answer
  • Find the equation for the line that passes through the point (−2,0), and that is perpendicular to the line with the equation 2/3
    8·1 answer
  • Twice Jack's age plus 5 is 21. Write and solve an equation. How old is Jack?
    14·2 answers
  • (4a^2b-3ab^2+2ab+5)+(2ab^2b+3ab^2-7ab)
    5·1 answer
  • Marco states that 7.696696669 is a rational number because it is a repeating decimal. is he correct
    13·2 answers
  • Find all real numbers x such that<br> 3x - 4 &gt; 5 and -8x - 19 &lt; 21
    9·1 answer
  • PLS HELP ASAP WILL GIVE BRAINLEAST!!!!!!!!
    9·1 answer
  • Someone Please help 2!!!!
    6·1 answer
  • 3:1 =6:x what is the value of x​
    6·2 answers
  • Need help ASAP please and thank you!
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!