Answer:
d. 60k
Step-by-step explanation:
The sample mean is the midpoint between the lower and the upper limit of the confidence interval, that is, the sum of the lower and the upper limit divided by 2.
In this problem, we have that:
Lower limit: 50k
Upper limit: 70k
(50k + 70k)/2 = 60k
So the correct answer is:
d. 60k
[tex]16210/60 (seconds) = 270.16
around $270
hope this helps
Answer:
p
Step-by-step explanation:
please help some one I also need help on this
For q(x) = -2x - 2 and r(x) = x^2 + 2
Find the value of q(r(3)).
This is a problem that asks for you to find a function of a function. First things first, you must understand that it is asking you to plug r(3) into q(x) as the value of x.
Let's start by plugging 3 into r(x). Doing so, you'd get
r(3) = 3^2 + 2
Solve it.
r(3) = 9 + 2
r(3) = 11
You can see now that q(r(3)) is really q(11). Plug it in.
q(r(3)) = -2(11) - 2
Solve it.
q(r(3)) = -22 - 2
q(r(3)) = -24

Any odd number can be represented with 2n+1 where n is a whole number. Also, since the next consecutive number will be even (2n+1+1), then the next consecutive odd number must be 2n+1+2, or 2n+3. Since consecutive odd numbers are separated by 2, then the previous odd number should be 2n-1. So:
<h3>2n-1+2n+1+2n+3=36</h3><h3>6n+3=36</h3><h3>6n+3-3=36-3</h3><h3>6n/3=33/3</h3><h3>2n=11</h3>
Now in order to find three odd consecutive numbers that will sum to 36, you must be able to divide 11 evenly by 2, and have a whole number as a result. This is impossible, so there aren't any 3 odd numbers that will sum to 36.
<h2>HOPE IT HELPS ☺️</h2>