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Sauron [17]
3 years ago
14

What is the equation of a quadratic graph with a focus of (-4,17/8) and a detric of y=15/8 answer

Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0

keeping in mind that the vertex is between the focus point and the directrix, in this cases we have the focus point above the directrix, meaning is a vertical parabola opening upwards, Check the picture below, which means the "x" is the squared variable.

now, the vertical distance from the focus point to the directrix is \bf \cfrac{17}{8}-\cfrac{15}{8}\implies \cfrac{2}{8} , which means the distance "p" is half that or 1/8, and is positive since it's opening upwards.

since the vertex is 1/8 above the directrix, that puts the vertex at \bf \cfrac{15}{8}+\stackrel{p}{\cfrac{1}{8}}\implies \cfrac{16}{8}\implies 2 , meaning the y-coordinate for the vertex is 2.

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\bf \begin{cases} h=-4\\ k=2\\ p=\frac{1}{8} \end{cases}\implies 4\left(\frac{1}{8} \right)(y-2)=[x-(-4)]^2\implies \cfrac{1}{2}(y-2)=(x+4)^2 \\\\\\ y-2=2(x+4)^2\implies \blacktriangleright y = 2(x+4)^2+2 \blacktriangleleft

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4th term of (4x-y)^9
Neko [114]
Now, let's do the same as we did for the previous one here.

\bf (4x-y)^9\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&+1&(4x)^9(-y)^0\\
2&+9&(4x)^8(-y)^1\\
3&+36&(4x)^7(-y)^2\\
4&+84&(4x)^6(-y)^3
\end{array}

notice again, how did we get 84 for the 4th element's coefficient? well 36 * 7 / 3.  and so on.  And you can just expand it from there.
3 0
3 years ago
a circle with radious of 1cm sits inside a 11cm times 12 cm rectangle what is the area of the shaded region
Nitella [24]

Answer: 128.86cm²

Step-by-step explanation:

The circle is inscribed in the rectangle. To find the shaded portion, subtract he area of the circle from the are of the rectangle.

Area of the rectangle                                  =  11 x 12

                                                                     =  132cm²

Area of the circle with radius of 1cm          =  πr²

                                                                     = 3.142 x 1²

                                                                     = 3.142cm²

Therefore , area of the shaded  region      = 132cm²  -  3.142cm²

                                                                    = 128.86cm²

7 0
3 years ago
Read 2 more answers
What's the answer??
baherus [9]
The first one: whole equation when move1 to the left, same with the second I believe
5 0
3 years ago
Jenny Pedaled her bike 11 miles in 45 minutes. if she traveled at the same speed, how far would she travel in 2 hours? Please sh
Anastaziya [24]
I believe the aswer is 29.7

1) 120 (2 hrs.in minutes) divided by 45
2) Round and multiply 2.7 by 11
3) Get your answer

         OR
1) 120 (2 hrs. n minutes) times 11
2) Divide by 45 and Get answer

6 0
3 years ago
20 points!!!!!!!
castortr0y [4]
See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid

we know that
One edge of the cuboid has length 2 cm----->  <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1

[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]

100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0

using a graph tool------> to resolve the second order equation
see the attached figure

the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm

<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm

the answer is
 the length of a diagonal of the cuboid is 13.75 cm



4 0
3 years ago
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