Now, let's do the same as we did for the previous one here.

notice again, how did we get 84 for the 4th element's coefficient? well 36 * 7 / 3. and so on. And you can just expand it from there.
Answer: 128.86cm²
Step-by-step explanation:
The circle is inscribed in the rectangle. To find the shaded portion, subtract he area of the circle from the are of the rectangle.
Area of the rectangle = 11 x 12
= 132cm²
Area of the circle with radius of 1cm = πr²
= 3.142 x 1²
= 3.142cm²
Therefore , area of the shaded region = 132cm² - 3.142cm²
= 128.86cm²
The first one: whole equation when move1 to the left, same with the second I believe
I believe the aswer is 29.7
1) 120 (2 hrs.in minutes) divided by 45
2) Round and multiply 2.7 by 11
3) Get your answer
OR
1) 120 (2 hrs. n minutes) times 11
2) Divide by 45 and Get answer
See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid
we know that
One edge of the cuboid has length 2 cm-----> <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1
[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]
100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm
<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm
the answer is the length of a diagonal of the cuboid is 13.75 cm