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riadik2000 [5.3K]
3 years ago
7

Evaluate the expression

Mathematics
2 answers:
agasfer [191]3 years ago
5 0

Solution :

\hookrightarrow \:  - { \bigg( \dfrac{1}{9} \bigg) }^{3}

\hookrightarrow \:  -  \dfrac{1}{729}

Brrunno [24]3 years ago
5 0

Answer:

-1/729

Step-by-step explanation:

{- ( \frac{1}{9})}^{3}  \\  =  - ( \frac{ {1}^{3} }{ {9}^{3}} ) \\  =  - ( \frac{1}{729}) \\  =  \frac{ - 1}{729}

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This year the boys’ basketball team won 4 times as many games as it lost. The team played a total of 40 games. How many games di
Salsk061 [2.6K]

Answer:

The team won 32 games.

Step-by-step explanation:

x = games won

y = games lost

z = total games = 40

x = 4y <em>Won 4 times as many games as it lost</em>

x + y = 40 <em>Games won + games lost = Total games played</em>

4y + y = 40 <em>Sub 4y in for x, as established previously</em>

5y = 40

y = 8

x = 4y

x = 4(8)

x = 32

The team won 32 games.

8 0
3 years ago
If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
goldenfox [79]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

3 0
2 years ago
45 + 30 = 100 - w<br> Answer correctly luvs
andrezito [222]

Answer:

the answer is 25

Step-by-step explanation:

45+30=100-w

then your going to subtract 45 on both sides. So 100-45 is 55.

so now your equation looks like this

30 = 55 - w

subtract 55 on both sides so you will have -25 = -w. Then your going to divide -w on both sides and you will have positive 25

i hope thus helps

7 0
2 years ago
Which expression represents 12 times a number, n, minus 6?
Ulleksa [173]

Answer:

A. 12n - 6

Step-by-step explanation:

12 times a number which is n so

12n then minus 6 ,

12n-6

hope this helps

6 0
2 years ago
Read 2 more answers
If x=-2 substitute the value of x into the expression and simplify
uranmaximum [27]

Answer:

-17

Step-by-step explanation:

the expression is 6x-5

Substituting x=-2

6(-2)-5

(-12)-5=-17

7 0
3 years ago
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