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Burka [1]
3 years ago
15

What is the slope intercept form of the linear equation that passes through the point (0, 9) and has a slope of -6?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

y - 9 = -6( x - 0)

y - 9 = -6x + 0

y = -6x + 9

Step-by-step explanation:

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Please simplify the following distributive property expression:
guapka [62]

You are correct


4(3x-5)

4(3x) + 4(-5)

12x-20

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3 years ago
Use the distributive property to multiply. Simplify your Answer.<img src="https://tex.z-dn.net/?f=%283y%20%2B%205%29%283y%5E%7B2
trapecia [35]
9y^3+6y^2-18y+15y^2+10y-30
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3 years ago
A total of 30000 tickets were sold for a concert of this amont 1/4 were sold for $1500 each 1/3 at $ 1000 each and the rest at $
Vinvika [58]

Answer:

12,600

Step-by-step explanation:

1/3 = 4/12

1/4 = 3/12

Together they equal 7/12

The different is 5/12

5/12 = .416666 =.42

.42 x 30,000 = 12,600

8 0
2 years ago
You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample
Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=160)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{160}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 1.96  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{1.96(160)}{78.4})^2 =16  

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And now we can replace the new value of Me and see what we got, like this:

n=(\frac{1.96*160}{60})^2 =27.32

And if we round up the answer we see that the value of n to ensure the margin of error required Me=\pm 60 $ is n=28.    

5 0
2 years ago
What is 3/5+3/8 in simplest form
schepotkina [342]
The answer would be 39/40.

1. Find the LCD of both of the fractions (LCD = 40)

2. Make the denominators the same as LCD (The LCD would be 40)

3. Simplify (24/40 + 15/40)

4. Join the denominators
(24 + 15/40)

5. Simplify (39/40)

In decimal form its 0.975.
5 0
3 years ago
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