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Lyrx [107]
3 years ago
15

Write the set of points from -5 to 4 but excluding -1 and 4 as a union of intervals

Mathematics
1 answer:
rjkz [21]3 years ago
5 0

We need to write interval for the number from -5 to 4.

We need to exclude numbers -1 and 4 from it.

First we need to note some important points about interval notation.

We need to check, which numbers are included and which numbers are excluded in the given interval.

We use open-interval ( or ) for excluded values and [ or ] close-interval for included values.

For the given problem, we have given three numbers: -5, -1 and 4.

It's clarly given that -1 and 4 are not included. But it is not said that -5 is excluded, so -5 is included number.

-1 comes in between -5 and 4 on the number line.

So let us write interval notation from -5 to -1. (Note : -5 is included and -1 excluded).

Therefore, we will write close interval " [ " on left side of -5 and an open interval " ( "on right side of -1. We get,

[-5 , -1 ).

Now, we will write interval notation from -1 to 4.

Both are excluced values, so we will take open intervals ( ) on left and right side of -1 and 4.

So, we get another part of the interval as

(-1,4).

We will put union symbol in between above two interval notations we get.

Therefore, final interval notation is

[-5 , -1 ) ∪ (-1,4).

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Answer:

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Step-by-step explanation:

Given expression:

12x \sqrt{900x^2y^4z^6}

\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:

\implies 12x \sqrt{900}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}

Replace 900 with 30² :

\implies 12x \sqrt{30^2}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}

\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:

\implies 12x \cdot 30|x|\sqrt{y^4}\sqrt{z^6}

\implies 360x|x|\sqrt{y^4}\sqrt{z^6}

(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).

\textsf{Apply exponent rule} \quad \sqrt{a^m}=a^{\frac{m}{2}}:

\implies 360x|x|\cdot y^{\frac{4}{2}}\cdot z^{\frac{6}{2}}

Simplify:

\implies 360xy^2|xz^3|

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).

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Read 2 more answers
Really struggling on this
navik [9.2K]
Angle 4 would be 77degrees because angle two is vertical to angle four.

Angle 3 and Angle 1 are equal because they are vertical to each other.

You would subtract 180 (degrees) minus 77 (degrees) and get 103 (degrees).

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You would get 180 degrees from the line.

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