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den301095 [7]
3 years ago
10

The point (2, 1) is a solution to which of the following systems of equations?

Mathematics
1 answer:
Tom [10]3 years ago
3 0
Well all you have to do is use 2 for all the x values and 1 for all the  y values and if the equations comes out true it is your answer
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You have a gift card for your favorite clothing store for the amount of $60. You have found a shirt you want for $15. You don't
Zolol [24]

Let

x--------> the amount you have left to spend

y--------> the cost of a shirt you want

z------> the amount of the gift card

we know that

x+y \leq   z --------> equation 1

y=\$ 15 --------> equation 2

z=\$ 60 --------> equation 3

Substitute the equation 2 and equation 3 in the equation [tex] 1 [/tex]

x+y \leq   z

x+15 \leq   60

therefore

<u>the answer is the option</u>

x+15 is less than or equal to 60

7 0
3 years ago
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Please look at number 10. from the slope and write the equation for me
kompoz [17]

Answer:

y = 8x + 38

Step-by-step explanation:

To find the slope we set up y = mx + b and plug m (our slope) in and then plug in the point into x and y to find b (our y-intercept)

   y = mx + b

   y = 8x + b

   6 = 8(-4) + b

   6 = -32 + b

+32   +32

 38 = b

So using our slope and our intercept we have our slope intercept

y = mx + b

y = 8x + 38

Hope this helps :)

7 0
3 years ago
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Divide. (35x^2 – 11x -8) divided by(5x+2)
Thepotemich [5.8K]
Attached you will see the answer (use polynomial division)
5 0
3 years ago
Can someone please fill in blank ASAP
Annette [7]

Answer:

The quotient is 48.

Step-by-step explanation:

Estimate the quotient using compatible numbers:

45 (or I guess any number close the answer above, not sure tbh)

Multiply the estimate by 21:

945

45*21

Is the estimate to high or too low?

too low

Adjust and continue until the product is 1008.

1008/21=48

Have a good day/evening! I hope my answer is correct!

8 0
1 year ago
Help for points and Ill give brainliest to correct!
Svetradugi [14.3K]

Answer:

D. 3 1/4

Step-by-step explanation:

5 0
3 years ago
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