Question

Verify the equation below with each of the values listed for z to find a solution . 3-2z=1/10

Answer 1

$3-2z=\frac{1}{10} \\30-20z=1\\-20z=-29 \\z=\frac{-29}{-20} \Longrightarrow z=\boxed{1.45}$

Answer 2

For this case we have the following equation:

$3-2z = \frac {1} {10}$

We must find the value of z that represents the solution of the equation:

We follow the steps below:

We multiply by 10 on both sides of the equation:

$10 (3-2z) = 1$

We apply distributive property to the terms of parentheses;

$30-20z = 1$

We subtract 30 from both sides of the equation:

$-20z = 1-30\\-20z = -29$

We divide between -20 on both sides of the equation:

$z = \frac {-29} {- 20}\\z = \frac {29} {20}\\z = 1.45$

If we substitute the value of z in the original equation, equality is satisfied.

Answer:

$z = 1.45$