Convert 3 1/3 into a improper fraction:
= 10/3
Then flip the other fraction around and multiply them together:
1/3 -> 3/1
(10*3)/(3*1) = 30/3 = (30/3)/(3/3) = 10/1 = 10
The answer is 10
Answer:
Cos(2115°) =1/√2
Sin(2115°) = -1/√2
Step-by-step explanation:
We have to find the values of Cos (2115°) and Sin (2115°).
Now, 2115° can be written as (23×90°+ 45°).
Therefore, the angle 2115° lies in the 4th quadrant where Cos values are positive and Sin values are negative.
Hence, Cos (2115°) = Cos(23×90° +45°) =Sin 45° {Since 23 is an odd number, so the CosФ sign will be changed to SinФ} =1/√2 (Answer)
Again, Sin (2115°) = Sin(23×90° +45°) = -Cos 45° {Since 23 is an odd number, so the SinФ sign will be changed to CosФ} = -1/√2 (Answer)
Now, the required reference angle is 45°. (Answer)
ANSWER- 83
Total : s+a = 322
Student tickets : s = 3a
Adult tickets : a = 332 - s
Answer:
Area of regular pentagon is 238.95 square inches.
Step-by-step explanation:
Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.
we know a regular polygon divides into 5 congruent triangles.
Side of pentagon i.e base of one triangle is 11.8 inches.
Also, distance from center to middle of side which is height of triangle is 8.1 inches.
Area of 1 triangle= ![\frac{1}{2}\times base\times height](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height)
= ![\frac{1}{2}\times 11.8\times 8.1](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%2011.8%5Ctimes%208.1)
= 47.79 sq inches.
Area of regular pentagon=area of 5 congruent triangles=
=238.95 sq inches.