Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:1st same 2nd same 3rd diffrent 4 the same
Step-by-step explanation:
A "roster" here is essentially a version of the set with all of elements listed out. Here, those elements are all of the odd numbers between 20 and 30, so our list would be
{21, 23, 25, 27, 29}
Answer:0.542=0.500 + 0.040+0.002
= \frac{5}{10} + \frac{4}{100} +\frac{2}{1000}
=5 tenth + 4 hundredths + two thousandths
One tenth = \frac{1}{10}
One Hundredth= \frac{1}{100}
One thousandth= \frac{1}{1000}
Step-by-step explanation:
Answer:
<u>6b - 4a + 22 units</u>
Step-by-step explanation:
Perimeter = 2(length + width)
= 2(3b - 4a + 5 + 6 + 2a)
= 2(3b - 2a + 11)
= <u>6b - 4a + 22 units</u>
