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3 years ago

Estimate the answer to: 341 ÷ 0.28

Mathematics

2 answers:

Snezhnost [94]3 years ago

4 0

Answer:

341 ÷ 0.28=1217,85714286

Step-by-step explanation:

Leona [35]3 years ago

4 0

340 divided by 0.3 = 1133.3

hope this helps xx

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The circumference of ruby's old swimming pool is 47.1 feet. Her new swimming pool has a diameter of 21 feet. How much larger is

Alla [95]

The new pool is 18.84 feet larger in circumference than the old one.

<u>Explanation:</u>

Given:

Circumference of the pool = 47.1 feet

Diameter of the new pool, d = 21 feet

radius, r = 21/2 feet

Circumference of the new pool = ?

We know:

Circumference = 2πr

where,

r is the radius

On substituting the value:

C = $2 X 3.14 X \frac{21}{2}$

C = 65.94 feet

The difference in circumference of the two pools = 65.94 - 47.1 feet

= 18.84 feet

Therefore, the new pool is 18.84 feet larger in circumference than the old one.

6 0

3 years ago

There are 20 baseball cards and 10 football cards on display at a sports museum. Noah says that

erica [24]

Answer:

They are both right becuase if you just take away 1 from 20 and 10 you get 2 and 1. For the 4:2 one take away 1 and mutiply by 2 equalling 4:2 but they are still the same thing.

Step-by-step explanation:

6 0

2 years ago

All of the functions shown below are either exponential growth or decay functions.

AlekseyPX

Answer:

Step-by-step explanation:

If an exponential function is in the form of y = a(b)ˣ,

a = Initial quantity

b = Growth factor

x = Duration

Condition for exponential growth → b > 1

Condition for exponential decay → 0 < b < 1

Now we ca apply this condition in the given functions,

1). $y=3.2(1+0.45)^{2x}$

Here, (1 + 0.45) = 1.45 > 1

Therefore, It's an exponential growth.

2). $y=(0.85)^{3x}$

Here, (0.85) is between 0 and 1,

Therefore, it's an exponential decay.

3). y = (1 - 0.03)ˣ + 4

Here, (1 - 0.03) = 0.97

And 0 < 0.97 < 1

Therefore, It's an exponential decay.

4). y = 0.5(1.2)ˣ + 2

Here, 1.2 > 1

Therefore, it's an exponential growth.

5 0

2 years ago

I know the answer is no solution but I don't know how to get it☹️ plz help!

Crank

When a linear equation is in the form y = mx + c, the c, or constant, is the intercept on the y axis, meaning it crosses the y axis at (0, 1).

The gradient (1/3 in this case) is how much the y increments (or decrements) per increase of 1 of the value of x.

This would mean that there would be one point at (0, 1), and another at (3, 2). Draw a line from these two points and beyond, and that is the graph sketched.

3 0

3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

3 years ago