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4 years ago

What are the ratios for sin A and cos A? The diagram is not drawn to scale.

Mathematics

2 answers:

vfiekz [6]4 years ago

8 0

<u>Answer:</u>

sin A = $\frac{15} {17}$ and cos A = $\frac{8}{17}$

<u>Step-by-step explanation:</u>

We are given a right angled triangle and we are to determine the ratios for sin A and cos A.

Sin is the ratio of perpendicular/hypotenuse while cos is the ratio of base/hypotenuse.

With respect to angle A, base = 8, perpendicular = 15 and hypotenuse = 17.

Therefore, $sin A = \frac{15}{17}$ and $cos A = \frac{8}{17}$ .

adoni [48]4 years ago

7 0

Answer:

sinA=15/17 and cosA=8/17

Step-by-step explanation:

sine is opposite side over hypotenuse and cosine is adjacent side over hypotenuse

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