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Montano1993 [528]
2 years ago
12

Evaluate 0.00048×0.81×10×(10)-7 ÷0.027×0.04x(10)6​

Mathematics
1 answer:
alexandr402 [8]2 years ago
5 0

Answer:

Step-by-step explanation:

0.00048*.81=0.0003888

0.0003888*10=0.003888

0.003888*(10)=0.3888

0.3888-7=-6.6112

-6.6112*0.027=-224.8592593

-224.8592593*0.04= -9.794370372

-9.794370372*(10)=-97.94370372

-97.94370372*6= -587.6622223

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Answer:

Option A is correct.

Value of S_{22} = 15.4

Step-by-step explanation:

Given: a_{12} = 2.4 and common difference(d) = 3.4

A sequence of numbers is arithmetic i.e,  it increases or decreases by a constant amount each term.

The sum of the nth term of a arithmetic sequence is given by;

S_n =\frac{n}{2}(2a+(n-1)d), where n is the number of terms, a is the first term and d is the common difference.

We also know the nth tern sequence formula which is given by ;

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First find a.

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Put n =12 and d=3.4 in equation [2] we have;

a_{12} = a+(12-1)(3.4)

a_{12} = a+(11)(3.4)

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S_{22} = \frac{22}{2}(2(-35)+(22-1)(3.4))

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S_{22} = (11)(-70+71.4)

S_{22} = (11)(1.4)

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S_{22} = 15.4

Therefore, the sum of sequence of 22nd term i.e, S_{22} = 15.4

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Answer:

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