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Tom [10]
3 years ago
5

3(q-7)=273(q−7)=27 find q

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

q = 16

Step-by-step explanation:

3(q - 7) = 27

3q - 21 = 27

3q = 27 + 21

3q = 48

q = 48/3

q = 16

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Write an equation of the line shown. Then use the equation to find the value of x when y = 150​
Ymorist [56]

Answer:

y = 10x + 30

x = 12

Step-by-step explanation:

The slope-intercept form formula, y = mx + b, can be used to write an equation for the line.

Where,

m = slope = \frac{y_2 - y_1}{x_2 - x_1}

b = y-intercept, which is the point at which the line intercepts the y-axis. At this point, x = 0.

Let's find the slope (m) using the coordinates of the two points given, (0, 30), (3, 60).

m = \frac{y_2 - y_1}{x_2 - x_1}

Let,

(0, 30) = (x_1, y_1)

(3, 60) = (x_2, y_2)

m = \frac{60 - 30}{3 - 0}

m = \frac{30}{3}

m = 10

y-intercept of the line, b = 30

Equation for the line would be:

y = 10x + 30

Using the equation, find x when y = 150.

Simply substitute the value for y in the equation to find x.

150 = 10x + 30

Subtract 30 from both sides

150 - 30 = 10x + 30 - 30

120 = 10x

Divide both sides by 10

\frac{120}{10} = \frac{10x}{10}

12 = x

x = 12

3 0
3 years ago
Which system of equations below has infinitely many solutions?
babymother [125]

Answer:

The third one

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The Perimeter of a triangle is 50 cm. One side is 7cm longer than the another side and 5 cm shorter than the third side. Find al
Aleksandr-060686 [28]
Imagine to have three segment: 1 is x, another is x+7 and the last is x-5. You know that their sum is 50, so you can write:

x+(x+7)+(x-5)=50
simplify:
3x+7-5=50
3x=48
x=16

16+7=23
16-5=11

So the thee sides are 11, 16 and 23.

Hope this helped.
6 0
3 years ago
Please solve these algebraic questions? THANKS
miskamm [114]

Step-by-step explanation:

Note: I'm only providing solutions for Problem 9.

<h2>9. Simplify the following by collecting like terms: </h2>

Combining like terms involve performing the required mathematical operations (using the PEMDAS rule).  The terms must have the same degree (or exponents).  

 

<h3>a) 3a + 7a  </h3>

Add the coefficients of both terms.  

3a + 7a  = 10a

<h3> </h3><h3>b) 4n + 3n </h3>

Add the coefficients of both terms.  

4n + 3n = 7n

<h3> </h3><h3>c) 12y - 4y </h3>

Subtract the coefficient of both terms.  

12y - 4y = 8y

<h3> </h3><h3>d) 5x + 2x + 4x </h3>

Add the coefficients of all terms.  

5x + 2x + 4x = 11x  

<h3 /><h3>e) 6ab - 2ab - ba </h3>

The last term, "ba," can be rewritten as, "ab."  Remember that with algebraic expressions such as "ab," it essentially involves multiplication of both variables within the same term. Thus, ab = a × b. The variables ab also have a numerical coefficient of 1:  1a × 1b.

Now, we can perform the subtraction on all terms:

6ab - 2ab - ab = 3ab.  

<h3 /><h3>f) 7mn + 2mn - 2mn </h3>

Subtract 2mn from 2mn, which leaves you with 7mn:

7mn + 2mn - 2mn = 7mn  

<h3 /><h3>g) 4y - 3y + 8 </h3>

For this algebraic expression, you could only combine the terms with the same variable and degree. Therefore, you'll have to subtract 3y from 4y, leaving the constant, 8, unaffected.  

4y - 3y + 8 = y + 8

 

<h3>h) 7x + 5 - 4x </h3>

Similar to question g, only combine the terms with the same degree and variable, leaving the constant unaffected.

7x + 5 - 4x = 3x + 5

<h3>i) 6xy + xy + 4y </h3>

You could only combine the terms with the same set of variables and degree, which are the first two terms on this given question. You cannot combine the last term, 4y, into the other terms.  

6xy + xy + 4y = 7xy + 4y

<h3>j) 5ab + 3 + 7ba </h3>

Using the same reasoning as in question e: the last term, 7ba, can be rewritten as 7ab, for which you could combine with the first term, 5ab.

5ab + 3 + 7ba = 12ab + 3  

<h3 /><h3>k) 2 - 5m - m  </h3>

Combine the like terms, which are the second and the last term.  

2 - 5m - m = 2 - 6m

<h3>l) 4 - 2x + x </h3>

Combine the like terms, which are the second and the last term.  

4 - 2x + x = 4 - x  

8 0
3 years ago
On an August day in Fairbanks, Alaska, the temperature changed by an average of 1.5° C per hour from its low of 5° C at 5:00 am.
zhuklara [117]

Answer:

9.5 C?

Step-by-step explanation:

im guessing since it's last change was an additional 4.5

5 0
3 years ago
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