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Tom [10]
3 years ago
5

3(q-7)=273(q−7)=27 find q

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

q = 16

Step-by-step explanation:

3(q - 7) = 27

3q - 21 = 27

3q = 27 + 21

3q = 48

q = 48/3

q = 16

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Use slopes and y-intercepts to determine if the lines 5x-5y=-2 and -x+2y=4
HACTEHA [7]

The given pair of lines are not perpendicular.

<h3>What is a line?</h3>

The line is a curve showing the shortest distance between 2 points.

5x - 5y = -2 - - - - - (1)
Transform the equation into standard form,
5x + 2 = 5y
y = 5x /5 + 2/5
y = x + 2/5


The slope of equation 1 is m_1 = 1  and intercept c = 2 / 5


Similarly
x + 2y = 4    - - - - - - - -(2)
Transform it into standard form
y = -x/2 + 4 /2
y = -x / 2 + 2


Slope of the equation 2  m_2= -1 / 2 and intercept c = 2
Slope of line 1 * slope of line 2 = 1 * -1/2 = -1/2


Since the lines are not perpendicular because the pair of lines does not satisfy the property of perpendicular lines i.e
m_1*m_2 = -1

Thus, the given pair of lines are not perpendicular.

Learn more about lines here:

brainly.com/question/2696693

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6 0
1 year ago
Complete the following sentence with a power of ten greater than 1. A kilometer is times as large as a millimeter. Click on the
Gelneren [198K]

Answer:

A kilometer is 10⁶ times as large as a millimeter.

Step-by-step explanation:

In the metric system first we have: millimeter, centimeter, decimeter and meter. Each one of these is 10 times the other (1 centimeter is 10 millimeter, 1 decimeter is 10 centimeter, 1 meter is 10 decimeter). Therefore, 1 meter is 10x10x10 millimeter = 1 meter is 1000 millimeters.

But we know that 1 km is 1000 meters,

Therefore, 1 km = 1000 meter = 1, 000,000 milimeter = 10⁶ milimeter

So then, we have that 1 kilometer is 10⁶ as large as a milimeter.

3 0
3 years ago
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VLD [36.1K]

Answer:

1. 1/1/5

2.1/3

3.3/10

4.2/3/5

5.2/9/20

6.1/15

4 0
3 years ago
Mr.Gleason's math class lasts 40 minutes.Math class starts at 9:55 A.M. At what time does math class end?
klio [65]
Math class ends at 10:35 am
5 0
3 years ago
Read 2 more answers
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
3 years ago
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