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AlladinOne [14]

3 years ago

8

The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distr

ibution. Test H0 : p1=p2 vs Ha : p1

1 answer:

gayaneshka [121]3 years ago

5 0

Answer:

-1.2

Step-by-step explanation:

I think i know what your asking. not sure if this is right. I'm sorry if it isn't..

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Subtract these sets of matrix

IrinaK [193]

The procedure is to make the difference of the terms that occupy the same position (column and row):

| - 6    - 4 |      | - 5    5 |              | - 6 + 5      - 4 - 5 |          | -1      - 9 |
| 6        0 | -   | - 4   -1 |     =       |   6 + 4     0 + 1 |    = | 10      1 |
| 6        4 |      | 6    - 4 |            |   6 - 6        4 + 4 |          | 0         8 |

Answer: option B.

8 0

2 years ago

X - (-20) = 5 _________________

tamaranim1 [39]

X - (-20) = 5

When you subtract a negative, change it to addition:

X + 20 = 5

Subtract 20 from both sides:

X = -15

8 0

2 years ago

Read 2 more answers

What is the correct answer can you guys help me I really need help on this?? Please

luda_lava [24]

The answer is 192 y^8.

(4y^2)^3 = 64y^6

64y^6 • 3y^2= 192y^8

When “multiplying” a number with an exponent, you add the 2 exponents.

3 0

3 years ago

A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the

Naya [18.7K]

Answer:

The area is growing at a rate of $\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 $\frac{cm}{min}$ and we identify such as the following differential rate:

$\frac{dr}{dt} = 3\,\frac{cm}{min}$

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find $\frac{dA}{dt}$ .

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

$A=\pi\,r^2$

We now apply the derivative operator with respect to time ( $\frac{d}{dt}$ ) to this equation, and use chain rule as we find the quadratic form of the radius:

$\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}$

Now we replace the known values of the rate at which the radius is growing ( $\frac{dr}{dt} = 3\,\frac{cm}{min}$ ), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

$\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\$

which we can round to one decimal place as:

$\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

4 0

3 years ago

If <br> f(x) = 7 sec x − 5x, find f '(x).

Lena [83]

F'(x) = 7sec x . tan x - 5.

6 0

3 years ago