Y = Ln (2x^3 + 3x)
then deriving
dy/dx= (1/(2x^3 + 3x))*(6x^2 + 3)
f(3) = 1
substitute x = 3 into f(x)
f(3) = (2 × 3) - 5 = 6 - 5 = 1
Answer: y=-x-1
Step-by-step explanation:
To find the answer, 5 and -6 have to be substituted in the place of x in the equation y = -x + b(The slope has to be the same because the line is parallel). -6 = -5 + b, b = -1. This means that the equation is y = -x - 1.
