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pochemuha
4 years ago
5

There are 500 students at Jacob's school. Jacob wants to conduct a survey of the students at his school to determine the level o

f interest in participating in a musical. Which of the following is most likely to produce a representative sample of students' interest in participating in the musical?
Mathematics
1 answer:
Feliz [49]4 years ago
5 0

Answer:

Step-by-step explanation:

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A gourmet pizza café sells three sizes of pizza: small, medium and large. To buy all three sizes, it costs a total of 46.95. If
sveta [45]

Answer:

its gowing to be eleven dollars an 46 sent11.46

6 0
3 years ago
Select the correct answer.
zysi [14]

Answer:

A.  -5x = -23

Step-by-step explanation:

First you have to simplify the equation - 4(x - 5) + 8x = 9x - 3

-4x + 20 + 8x = 9x -3

9x - 4x = 20 + 3

5x = 23

=> equivalent to answer A.

8 0
2 years ago
Use complete sentences to describe why √-1≠-√1
Salsk061 [2.6K]

Answer: because √-1 complex number ; and -√1 real number

Step-by-step explanation:

because √-1 complex number ; and -√1 real number or                                         \displaystyle\ (\sqrt{-1})^2 \neq(- \sqrt{1} )^2 \\\\-1\neq 1                                              

7 0
3 years ago
Which number will come next 4, 5, 9, 18, 34, 59…?
GaryK [48]

Answer: 95

34 + 59 = 95

6 0
3 years ago
ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
  (5/8 -1/6 -1/12)AB·h = 30 cm²
  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
6 0
3 years ago
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