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3 years ago

HELP ASAP PLEASE!!! THE PRODUCT OF 3! IS A. 1 B. 2 C. 3 D. 6

Mathematics

1 answer:

Kipish [7]3 years ago

8 0

Answer:

D. 6

Step-by-step explanation:

! means take the number listed before the factorial symbol , list all the integers down to 1 and multiply

3! = 3*2*1

= 6

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Find the value of x to the nearest tenth will mark brainliest

Orlov [11]

Answer:

B. 5.4

Step-by-step explanation:

3/5 = 6/10

6/10 = 0.6

9 x 0.6 = 5.4

7 0

3 years ago

Need help pretty please

Ainat [17]

Answer:

The answer is 180 degress

Step-by-step explanation:

This is because, all triangle angles, no matter what kind of triangle it is all angles add up to 180

8 0

3 years ago

Help would be nice, i’m out of school from covid

Mashcka [7]

SOLUTION:

We are to pick from the given tiles the pairs that are associated with each functions.

Note that each of the pairs are of the form (x,y) coordinates.

(1)

$y=6^x$

The correct tiles for this function with explanation are given as follow;

$\begin{gathered} (1,6)\text{ } \\ y\text{ = 6 when x =1 } \\ y=6^x \\ 6=6^1 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (0,1) \\ y\text{ = 1 when x = 0} \\ y=6^x \\ 1=6^0 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (2,36) \\ y=36\text{ when x = 2} \\ y=6^x \\ 36=6^2 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (0.5,\sqrt[]{6)} \\ y\text{ = }\sqrt[]{6}\text{ when x = 0.5} \\ y=6^x \\ \sqrt[]{6}=6^{0.5} \\ \sqrt[]{6}=6^{\frac{1}{2}} \\ \sqrt[]{6}\text{ = }\sqrt[]{6} \\ \text{Correct} \end{gathered}$

For the first function, above tried tiles are the associated ones any other one different from those explained above are not associated with the fuction.

(2)

$y=\log _6x$

The correct tiles for this function are given as follow;

$(6,1),\text{ (1, 0), (36 ,2) and (}\sqrt[]{6\text{ }}\text{ , 0.5)}$

Let me explain or prove two out of the four tiles.

$\begin{gathered} (6,\text{ 1)} \\ y\text{ = 1 when x =6} \\ y=\log _6x \\ 1=\log _66 \\ \text{Correct} \end{gathered}$ $\begin{gathered} (\sqrt[]{6},\text{ 0.5)} \\ y\text{ = 0.5 when x = }\sqrt[]{6} \\ y=\log _6x \\ 0.5\text{ =}\log _6\sqrt[]{6} \\ \frac{1}{2}=\log _66^{\frac{1}{2}} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\log _66 \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ x 1} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ } \\ \\ \text{Correct} \end{gathered}$

You can also use the approach above to confirm the remaining two.

5 0

1 year ago

No fake answer plz

Ilia_Sergeevich [38]

<h3>Answer:</h3>

There are more red marbles in the bag.

<h3>Explanation:</h3>

The fraction of red marbles is 1/3 = 3/9. That is a larger fraction than the fraction of green marbles, which is 2/9.

8 0

3 years ago

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