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3 years ago

How do I divide £56 in a ratio of 5:3??

Mathematics

1 answer:

givi [52]3 years ago

7 0

By answering right somebody question!!

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Find what n equals 8(2n-2) = 4 - 4n (explanation please)

slavikrds [6]

Answer:

$\huge\boxed{n=1}$

Step-by-step explanation:

In order to find the value of n that satisfies this equation, we can perform a series of algebraic steps on it to solve for n.

$8(2n-2) = 4- 4n$
Distribute in the 8 on the left side:
$16n-16=4-4n$
Add 4n to both sides
$20n-16=4$
Add 16 to both sides
$20n = 20$
Divide both sides by 20
$n=1$

Therefore, n=1 is the value of n that satisfies this equation.

Hope this helped!

6 0

3 years ago

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Convert 11.42424242 … to a rational expression in the form of a over b, where b ≠ 0.

Pavlova-9 [17]

x=11.4242....

100x=1142.4242....

100x-x = 99x = 1131

x=1131/99 = 11 42/99 (unreduced) = 11 14/33 (reduced fraction)

7 0

3 years ago

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A right triangle has a hypotenuse of 10 cm and one leg that measures 5 square 3 what is the length of the other leg

guajiro [1.7K]

I hope this helps you

3 0

3 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

3 years ago

Find the value of x and y. Identify the type of angle pair!!

alex41 [277]

Answer:

y = 3

x = 5

Step-by-step explanation:

40y + 20 = 60 y - 40 because opposite angles are equal

solve this equation

40y + 60 = 60 y

60 = 20 y

3 = y

8x = 2x +30

6x = 30

x = 5

3 0

3 years ago

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