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prohojiy [21]
3 years ago
5

Parker marks sixths on number line. He writes 5/6 just before 1. What fraction does he write on the first mark to the right of 1

?
Mathematics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

The first fraction at the right of 1 is \frac{7}{6} or 1\frac{1}{6}

Step-by-step explanation:

Given

Marks of 6ths on a number line

Fraction 5/6 just before 1

Required

What fraction is at the right 1

To get the first fraction at the right of 1, we need to get the difference between each fraction;

This is calculated as follows;

Difference = 1 - \frac{5}{6}

Take LCM

Difference = \frac{6 - 5}{6}

Difference = \frac{1}{6}

This implies that the difference between each mark is \frac{1}{6}.

To get the first mark at the right of 1;

We simply add the difference to 1;

This implies that;

Mark = 1 + \frac{1}{6}

Take LCM

Mark = \frac{6 + 1}{6}

Mark = \frac{7}{6}

Convert to mixed fraction

Mark = 1\frac{1}{6}

Hence, the first fraction at the right of 1 is \frac{7}{6} or 1\frac{1}{6}

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Given:

The equation of a line is:

y=-\dfrac{5}{7}x+2

A line passes through the point (-5,-3) and perpendicular to the given line.

To find:

The equation of the line.

Solution:

Slope intercept form of a line is:

y=mx+b                 ...(i)

Where, m is the slope and b is the y-intercept.

We have,

y=-\dfrac{5}{7}x+2          ...(ii)

On comparing (i) and (ii), we get

m=-\dfrac{5}{7}

We know that the product of slopes of two perpendicular lines is always -1.

m_1\times m_2=-1

-\dfrac{5}{7}\times m_2=-1

m_2=\dfrac{7}{5}

Slope of the required line is \dfrac{7}{5} and it passes through the point (-5,-3). So, the equation of the line is:

y-y_1=m_2(x-x_1)

y-(-3)=\dfrac{7}{5}(x-(-5))

y+3=\dfrac{7}{5}(x+5)

Using distributive property, we get

y+3=\dfrac{7}{5}(x)+\dfrac{7}{5}(5)

y+3=\dfrac{7}{5}x+7

y=\dfrac{7}{5}x+7-3

y=\dfrac{7}{5}x+4

Therefore, the equation of the line is y=\dfrac{7}{5}x+4. Hence, option A is correct.

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"The product of two numbers is 169. If the L.C.M. of these numbers is 13, find their H.C.F. "
umka21 [38]

Answer:

13

Step-by-step explanation:

HCF = Product of two numbers ÷  LCM of these numbers

HCF = \frac{169}{13}

        = 13

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Read 2 more answers
What is the radius of a circle whose equation is x 72 y 102 4
almond37 [142]

The circle of the given radius with equation (x-7)²+(y-10)²=4 is 2 units.

<h3>What do we mean by circles?</h3>

A circle is, in the simplest terms, a circular shape without edges or lines.

Its geometric form is that of a closed curve.

If you track a moving point in a plane while keeping a fixed distance from another point, a circle will have a closed shape.

The English word "circle" derives from the Greek word "kirks," which means "hoop" or "ring."

So, the equation for a circle in its standard form is:

(x - h)² + (y - k)² = r²

Where the radius is r and the centroid is (h, k).

The equation is: (x - 7)² + (y - 10)² = 4

This is rewritten as:

(x - 7)² + (y - 10)² = 2²

When compared to the typical form:

(h, k) = (7, 10)

The circle's radius is 2.

Therefore, the circle of the given radius with equation (x-7)²+(y-10)²=4 is 2 units.

Know more about circles here:

brainly.com/question/24375372

#SPJ4

Correct question:
What is the radius of a circle whose equation is (x-7)²+(y-10)²=4?

8 0
1 year ago
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