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romanna [79]
3 years ago
13

5x+6+1x in simplest form

Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0
5x+6+1x
= (5x+1x)+ 6 (combine like terms)
= 6x+6
= 6(x+1) (distributive property)

The final answer is 6(x+1)~
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Can someone answer this please and thank you
musickatia [10]

Answer:

See below.

Step-by-step explanation:

x+3/9=5/9

  -3/9  -3/9

x=2/9

--------------

11+x=50

-11     -11

x=39

-------------

2/9+x=8/9

-2/9     -2/9

x=6/9 or 2/3

-hope it helps

7 0
2 years ago
For the sequence 3n - 1, generate the first three terms.
Hunter-Best [27]
3n - 1

When n = 1,

3n - 1 = 3*1 - 1 = 3 -1 = 2

When n = 2,

3n - 1 = 3*2 - 1 = 6 -1 = 5

When n = 3,

3n - 1 = 3*3 - 1 = 9 -1 = 8

Hence, the first three terms are 2, 5 and 8.
5 0
3 years ago
Question 4*
inessss [21]

Answer:

D

Step-by-step explanation:

6 0
2 years ago
How do you integrate 7xe^-5x²?
Nana76 [90]
Making assumptions about where parentheses should be, 
<span>Let u = -7x </span>
<span>du = -7dx </span>
<span>dv = e^(2x) dx </span>
<span>v = e^(2x)/2 </span>
<span>∫ -7xe^(2x) dx = </span>
<span>-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx = </span>
<span>-7xe^(2x)/2 + 7e^(2x)/4 + c</span>
3 0
2 years ago
1.13 Thank you! (Sorry it’s so blurry)
VikaD [51]
\sqrt[8]{48^4}  can be rewritten as 48^4 to the \frac{1}{8}  power:

(48^4)^ \frac{1}{8}

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

(48^ \frac{1}{2})

This is equivalent to \sqrt{48}, so now, we just simplify:

\sqrt{48}=  \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}

So:

\sqrt[8]{48^4} =4 \sqrt{3} 


4 0
3 years ago
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