<h3>Answer: 1/6</h3>
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Explanation:
There are two methods to approach this type of problem.
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Method 1
A = junior
B = girl
P(A) = probability of selecting a junior
P(B) = probability of selecting a girl
P(B) = (number of girls)/(number total)
P(B) = (4+7+3+4)/(4+4+5+7+2+3+1+4)
P(B) = 18/30
P(B) = 9/15
P(A and B) = probability of selecting a girl who is a junior
P(A and B) = (number of girl juniors)/(number total)
P(A and B) = 3/30
P(A and B) = 1/10
P(A given B) = P(A and B)/P(B)
P(A given B) = (1/10) divided by (9/15)
P(A given B) = (1/10) times (15/9)
P(A given B) = (1*15)/(10*9)
P(A given B) = 15/90
P(A given B) = 1/6
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Method 2
This method doesn't involve dividing two fractions which could get messy, which is why I find this the easier route. Since we are given the person is a girl, this means we only need to focus on the "girls" column. There are 3 who are juniors out of 4+7+3+4 = 18 total. The probability of selecting a girl junior is 3/18 = 1/6