A salesperson starts at the office and travels to 5 customers along a road. The positive numbers stand for going East. The negat
ive numbers stand for going West. Which expression gives the total number of miles she travels to see these 5 customers?
a.|5+8+2 1/2+6 1/4+-3/4|
b.5-8+2 1/2-6 1/4-3/4
c.|5|+|8|+|2 1/2|+|6 1/4|+|3/4|
d.|(5)+(8)+(2 1/2)+(-6 1/4)+(-3/4)|
a.|5+8+2 1/2+6 1/4+-3/4|
b.5-8+2 1/2-6 1/4-3/4
c.|5|+|8|+|2 1/2|+|6 1/4|+|3/4|
d.|(5)+(8)+(2 1/2)+(-6 1/4)+(-3/4)|
2 answers:
You might be interested in
Part A
The given line passes through (-2,2) and it is parallel to the line
We need to determine the slope of this line by writing it in slope -intercept form.
The slope of this line is
The line parallel to this line also has slope
The equation is
We substitute (-2,2)
The required equation is
PART B
The given line is
The slope of this line is
The slope of the line perpendicular to it is
The equation of the line is
We substitute the point, (-2,2)
The equation of the perpendicular line is
The given line passes through (-2,2) and it is parallel to the line
We need to determine the slope of this line by writing it in slope -intercept form.
The slope of this line is
The line parallel to this line also has slope
The equation is
We substitute (-2,2)
The required equation is
PART B
The given line is
The slope of this line is
The slope of the line perpendicular to it is
The equation of the line is
We substitute the point, (-2,2)
The equation of the perpendicular line is
Answer:
(a) <em> </em><em>n</em> : 20 50 100 500
P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886 0.4444 0.5954 0.9376
(b) The correct option is (b).
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.
The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.
Assuming that the random variable <em>X </em>follows a normal distribution.
(a)
Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:
- For a sample size of <em>n</em> = 20
- For a sample size of <em>n</em> = 50
- For a sample size of <em>n</em> = 100
- For a sample size of <em>n</em> = 500
<em> n</em> : 20 50 100 500
P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886 0.4444 0.5954 0.9376
(b)
The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample () approaches the whole population mean (
).
Consider the probabilities computed in part (a).
As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.
So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.
Thus, the correct option is (b).