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Free_Kalibri [48]
3 years ago
14

If 2^x=5 what is 2^3^x - 4

Mathematics
2 answers:
solmaris [256]3 years ago
7 0

Answer: 121

Step-by-step explanation:

If 2^x = 5, what is the value of 2³^×

This can also be re arranged in the form

(2^x)³ - 4

Since 2^x = 5, we now substitute for the value in the expression above.

5³ - 4

= 125 - 4

= 121.

vivado [14]3 years ago
6 0
I believe the answer is 26
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Rachel bought turkey for a cookout she used the turkey to make 1/4 pound burgers if Rachel bought 4 1/2 pounds of turkey how man
zysi [14]

Answer:

the answer is 18 burgers

Step-by-step explanation:

u have to do 4 1/2÷1/4=18 burgers

Hope this helps!!!

6 0
3 years ago
If sin y° = 7 over q and tan y° = 7 over r, what is the value of sec y°?
Tomtit [17]

Answer:

Sec y = q/r

Step-by-step explanation:

Sin y = 7/q

tan y = 7/r

Mathematically cos y = sin y/tan y

But sec y = 1/cos y

So therefore sec y = tan y/sin y

So that would be ;

7/r divided by 7/q

= 7/r * q/7

= q/r

3 0
3 years ago
Which expression can be used to find the price of a $400 telescope after a 32% markup? Select all that apply.
elena-s [515]
<h3>There are 2 answers: choice C, choice D</h3>

====================================================

Explanation:

32% = 32/100 = 0.32

32% of 400 = 0.32*400 = 400(0.32), which adds onto the original 400 to get 400+400(0.32). This is why choice D is one of the answers.

We can factor out the GCF 400 to go from 400+400(0.32) to 400(1+0.32) which then simplifies to 400(1.32) or just 400*1.32. This shows choice C is the other answer. Using a calculator,

400+400(0.32) = 400 + 128 = 528

400*1.32 = 528

meaning that 400+400(0.32) = 400*1.32

The other answer choices result in other values, showing that they aren't equivalent to 528.

6 0
4 years ago
Write a rule for the linear function in the table.
JulijaS [17]

Answer:

I guess that you want to know the transformations:

We start with:

f(x) = y = 4*x + 3

a)the transformed function is:

f(x) = y = -4*x - 3

So the sign changed.

This means that we go from (x, y) to (x, - y)

This is a reflection over the x-axis which changes the sin of the y component.

b) Now we go to f(x) = 4*x + 3

So the coefficient in the leading term changed.

This is a horizontal contraction:

A horizontal contraction of factor K for the function g(x) is: g(K*x)

In our case, we have:

f(K*x) = 4*(k*x) + 3 = x + 3

4*k*x = x

4*k = 1

k = 1/4

Then the transformation is an horizontal contraction of scale factor 1/4.

6 0
3 years ago
For 0 ≤ ϴ &lt; 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va
Black_prince [1.1K]

Answer:

3 solutions:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is tan(\frac{\theta}{2}) so let's focus on that part of the equation first.

We know that:

tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}

therefore:

cos(\frac{\theta}{2})\neq0

so we need to find the angles that will make the cos function equal to zero. So we get:

cos(\frac{\theta}{2})=0

\frac{\theta}{2}=cos^{-1}(0)

\frac{\theta}{2}=\frac{\pi}{2}+\pi n

or

\theta=\pi+2\pi n

we can now start plugging values in for n:

\theta=\pi+2\pi (0)=\pi

if we plugged any value greater than 0, we would end up with an angle that is greater than 2\pi so,  that's the only angle we cannot include in our answer set, so:

\theta\neq \pi

having said this, we can now start solving the equation:

tan(\frac{\theta}{2})=sin(\theta)

we can start solving this equation by using the half angle formula, such a formula tells us the following:

tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}

so we can substitute it into our equation:

\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)

we can now multiply both sides of the equation by sin(\theta)

so we get:

1-cos(\theta)=sin^{2}(\theta)

we can use the pythagorean identity to rewrite sin^{2}(\theta) in terms of cos:

sin^{2}(\theta)=1-cos^{2}(\theta)

so we get:

1-cos(\theta)=1-cos^{2}(\theta)

we can subtract a 1 from both sides of the equation so we end up with:

-cos(\theta)=-cos^{2}(\theta)

and we can now add cos^{2}(\theta)

to both sides of the equation so we get:

cos^{2}(\theta)-cos(\theta)=0

and we can solve this equation by factoring. We can factor cos(\theta) to get:

cos(\theta)(cos(\theta)-1)=0

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

cos(\theta)=0

\theta=cos^{-1}(0)

\theta={\frac{\pi}{2}, \frac{3\pi}{2}}

Equation 2:

cos(\theta)-1=0

we add a 1 to both sides of the equation so we get:

cos(\theta)=1

\theta=cos^{-1}(1)

\theta=0

so we end up with three answers to this equation:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

7 0
3 years ago
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