Answer:
(x, y) = (2, 4) or (-1, 1)
Step-by-step explanation:
y = x^2
y = x + 2
=> x^2 = x + 2
Transfer all terms to the left, we have:
=> x^2 - x - 2 = 0
Perform some modifications, we have:
=> x^2 + x - 2x - 2 = 0
Let's group the left-side terms up.
=> x(x + 1) - 2(x + 1) = 0
=> (x - 2)(x + 1) = 0
=> x = 2 => y = x + 2 = 2 + 2 = 4
=> x = -1 => y = x + 2 = -1 + 2 = 1
=> Solution is (x, y) = (2, 4) or (-1, 1)
Hope this helps!
