Answer:
Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
The option is
4. 270≤Ф≤360
Step-by-step explanation:
When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.
For Example.
Quadrant I - 0 to 90°
Quadrant II - 90° to 180°
Quadrant III - 180° to 270°
Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360 )
Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.
Quadrant IV - 0° to -90°
Quadrant III - - 90° to -180°
Quadrant II - -180° to -270°
Quadrant I - -270° to -360°
The answer is
A. 3x - y= -7
<h3>
Answer: 42</h3>
Explanation:
We have y = -0.9x^2 + 76x - 250 which is in the form y = ax^2+bx+c
where,
The vertex (h,k) is when the profit is maxed out.
h = -b/(2a)
h = -76/(2(-0.9))
h = 42.222 approximately
Let's plug in x values around x = 42
Try x = 41
y = -0.9x^2 + 76x - 250
y = -0.9(41)^2 + 76(41) - 250
y = 1353.10
Now try x = 42
y = -0.9x^2 + 76x - 250
y = -0.9(42)^2 + 76(42) - 250
y = 1354.4
Now try x = 43
y = -0.9x^2 + 76x - 250
y = -0.9(43)^2 + 76(43) - 250
y = 1353.9
We see that the largest profit happens when x = 42.
The distance flown by plane is 750 kilometers.
Step-by-step explanation:
Let,
Distance traveled by plane = x
Distance traveled by car = y
Total distance = x+y
According to given statement;
The distance by car was 125 kilometers less than the distance by plane.
y = x - 125 => x=y+125 Eqn 1
The total distance was 500 kilometers less than three times the distance traveled by car.
Total distance = 3y - 500
x+y=3y-500 Eqn 2
Putting value of x from Eqn 1;
Putting y=625 in Eqn 1
The distance flown by plane is 750 kilometers.
Keywords: linear equations, substitution method
Learn more about linear equations at:
#LearnwithBrainly
Substitute (-1)3-(-1)+(-1)0
multiply (-3)+1+0
simplify. -2
Final Answer: -2
