2 heads and tails. time 5 times is 10. so 10 combos
A.) A= (1/2)absinC
b.) sinA/a, sinB/b, sinC/c
sin100/42, sin25/b, sinC/c
use these two fractions.
sin100/42= sin25/b
cross multiply next
b×sin100= 42×sin25
then divide on both sides by sin100
b=18
c.)measurementofA+measurementofB+measurementofC=180
100+25+C=180
125+C=180
-125 -125
The measurement of angle C is 55 degrees.
d.)A=(1/2)42×18×sin55
= 21×18×sin55
A =309.6 units squared
Answer:
C
Step-by-step explanation:
I hope it's right
Sorry if it's wrong
Would use the algorithm for solving square root.
For square root, √n
x₁ = 0.5(x₀ + n/x₀)
(This formula is known and for square root, and can be derived using Newton-Raphson's approximation equation)
Where x₀ is the initial guess. x₁ becomes the new guess.
For √100.6 let our initial guess be 10, x₀ = 10, n = 100.6
Our approximation shall be to 3 decimal places. Once we get the same answer twice we stop the algorithm.
x₀ = 10, x₁ = 0.5(x₀ + n/x₀), x₁ = 0.5(10 + 100.6/10) = 10.030, x₁ = 10.030
x₂ = 0.5(x₁ + n/x₁), x = 0.5(10.030 + 100.6/10.030) ≈10.015, x₂ ≈ 10.030 (to 3 decimal places)
Since x₂≈ x₁, the algorithm stops.
So the √100.6 is ≈ 10.030 to 3 decimal places.
I hope this helps.
